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elena-s [515]
4 years ago
7

What is the numerator of the fraction equivalent to 3\5 that has a denominator of 30

Mathematics
1 answer:
aliya0001 [1]4 years ago
3 0
Well, the numerator is the number on top, so in the fraction 3/5, 3 is the numerator. To find the equation with a denominator of 30 that is equivalent, find what the difference is. 30/5 = 6. So now, multiply the numerator by 6. 6 * 3 = 18. The new fraction is 18/30. The numerator is 18. Hope this helps!
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a) How many significant figures are in the numbers 99 and 100? (b) If the uncertainty in each number is 1, what is the percent u
levacccp [35]

Answer:

2, 3

1.01, 1

Percentage uncertainty

Step-by-step explanation:

a) The significant figures in the number 99 is 2

The significant figures in the number 100 is 3

b) Uncertainty in each of the numbers for both the numbers is 1

Percentage uncertainty

99

\text{Percentage uncertainty}=\frac{\text{Uncertainty}}{Value}\times 100 \\\Rightarrow \text{Percentage uncertainty}=\frac{1}{99}\times 100=1.01

Percentage uncertainty = 1.01

100

\text{Percentage uncertainty}=\frac{\text{Uncertainty}}{Value}\times 100 \\\Rightarrow \text{Percentage uncertainty}=\frac{1}{100}\times 100=1

Percentage uncertainty = 1

c) Percentage uncertainty is a better way to express the numbers as the significant figures do not show the actual value of the numbers.

6 0
4 years ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

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\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

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\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

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\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

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3 years ago
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galben [10]

Answer:

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Step-by-step explanation:

You are basically combining like terms

8 0
3 years ago
Read 2 more answers
Can somebody help me?
Black_prince [1.1K]

Answer:

C) v≤-5

Step-by-step explanation:

4v\leq -20

Divide each side by 4,

v\leq -5

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3 years ago
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viva [34]
Use two points to find the slope
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