The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer:
C
Step-by-step explanation:
First we find the z-score.
z = (x - μ) / σ
z = (520 - 500) / 60
z = 0.33
Using a calculator or z-score table:
P(z < 0.33) = 0.6293
The probability is approximately 63%. Answer C
For the first one it is 200% because he walked twice as much today than yesterday. For the second one the answer is yes with a 14.49. (I'm not sure on the second.)
Answer:
5353 ft
Step-by-step explanation:
We have height of the mountain = x
We also have
tan (21°44')= x/13428.7 → x=5352.98ft
Height of the mountain to the nearest foot = 5353 ft
Hope this helps ʕ•ᴥ•ʔ
