(a) Take the Laplace transform of both sides:


where the transform of
comes from
![L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)](https://tex.z-dn.net/?f=L%5Bty%27%28t%29%5D%3D-%28L%5By%27%28t%29%5D%29%27%3D-%28sY%28s%29-y%280%29%29%27%3D-Y%28s%29-sY%27%28s%29)
This yields the linear ODE,

Divides both sides by
:

Find the integrating factor:

Multiply both sides of the ODE by
:

The left side condenses into the derivative of a product:

Integrate both sides and solve for
:


(b) Taking the inverse transform of both sides gives
![y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]](https://tex.z-dn.net/?f=y%28t%29%3D%5Cdfrac%7B7t%5E2%7D2%2BC%5C%2CL%5E%7B-1%7D%5Cleft%5B%5Cdfrac%7Be%5E%7Bs%5E2%7D%7D%7Bs%5E3%7D%5Cright%5D)
I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that
is one solution to the original ODE.

Substitute these into the ODE to see everything checks out:

Answer:
GI = 18; GE = 12; IE = 6
Step-by-step explanation:
The key to the question is to realize or find out what a centroid is and what it does. You can solve this question by knowing three things.
- The centroid is the meeting point of the three medians ( a median is a line that connects the midpoint of the side opposite a given vertex).
- The centroid divides the median in a ratio of 2:1. The longest segment is from the vertex to the centroid.
- The shortest segment is from the centroid to the midpoint of the side opposite the given vertex.
Point two is what you have to focus on.
GE/EI = 2/1
GE = 12 Given
Solution
GE / EI = 2/1 Substitute for the given
12 / EI = 2/1 Cross multiply
2*EI = 12 * 1 Simplify the right
2 * EI = 12 Divide by 2
EI = 12/2 Divide
Part Two
GI = EI + GE
GI = 6 + 12
GI = 18
EI = 6
Answer:
5,4,3,2,1
Step-by-step explanation:
Answer:
Step-by-step explanation:
- We are to find the time (number of minutes) is would take for 23 mg of the substance to be remaining.
- The formula for time is written as:
t = [t1/2 x In(Nt/No)] / In 2
where:
t1/2 = Half life = 4 minutes
No = Initial quantity of the sample = 90 mg
Nt = Amount of the sample left = 23 mg
t = time elapsed = ?
Hence,
t = [4 x In (23/90)] / -In 2
t = 7.8731645610906 minutes
Approximately to the nearest hundredth = 7.87 minutes
Therefore, there will be 23mg of substance remaining after 7.87 minutes.
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