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Bingel [31]
2 years ago
7

What are the solutions to the system of equations below 3y=x-2 y=-2x+4

Mathematics
1 answer:
Oduvanchick [21]2 years ago
7 0

The value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have a system of the equation:

3y=x-2 ..(1)

y=-2x+4  ...(2)

From the equation (2) take the value of y and plug in the equation (1)

3(-2x+4) = x -2

-6x + 12 = x - 2

7x = 14

x = 14/7

x = 2

Plug this value in the equation (2)

y = -2(2) + 4

y = 0

Thus, the value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

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\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad  \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$600\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\to &1\\ t=years\to &8 \end{cases} \\\\\\ A=600\left(1+\frac{0.08}{1}\right)^{1\cdot 8}\implies A=600(1.08)^8\implies A\approx 1110.558126

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