What are the solutions to the system of equations below 3y=x-2 y=-2x+4
1 answer:
The value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
<h3>What is a linear equation?</h3>It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have a system of the equation:
3y=x-2 ..(1)
y=-2x+4 ...(2)
From the equation (2) take the value of y and plug in the equation (1)
3(-2x+4) = x -2
-6x + 12 = x - 2
7x = 14
x = 14/7
x = 2
Plug this value in the equation (2)
y = -2(2) + 4
y = 0
Thus, the value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
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Answer
Find out the which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .
To proof
As given in the question
Let us assume that the number of hours charged at the day rate = d
Let us assume that the number of hours charged at the night rate = n
An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.
Total working hour in a company including day and night be 12 hours .
than the equation become in the form
d + n = 12
also
An online data base charges $25 an hour during the day
$12.50 an hour at night.
If a research company paid $250 for 12 hours of use.
than the equation becomes
25d + 12.50n = 250
than the two equation are
d + n = 12 , 25d + 12.50n = 250
multiply first by 25 and subtracted from 25d + 12.50n = 250
25d - 25d + 12.50n - 25n = 250 - 300
12.5 n = 50
n = 4hours
put this in the d + n = 12
d + 4 =12
d = 12-4
d = 8 hours
Therefore the number of hours charged at the day rate is 8 hours and at the night rate is 4hours .
Hence proved