What are the solutions to the system of equations below 3y=x-2 y=-2x+4
1 answer:
The value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
<h3>What is a linear equation?</h3>It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have a system of the equation:
3y=x-2 ..(1)
y=-2x+4 ...(2)
From the equation (2) take the value of y and plug in the equation (1)
3(-2x+4) = x -2
-6x + 12 = x - 2
7x = 14
x = 14/7
x = 2
Plug this value in the equation (2)
y = -2(2) + 4
y = 0
Thus, the value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
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Answer:
8 years approximately
The problem (I'm assuming is):
Solve .
I put a t in the problem where I suspected it in went.
Step-by-step explanation:
Divide both sides by 100:
Rewrite in logarithm form.
Divide both sides by 0.05:
Put left hand side into calculator:
So about 8 years if I wrote down the equation correctly.