Problem set A: A=6 and B=2
6=AxB^0 [6=6x1]
24=AxB^2= [24=6x2^2]
Problem set B: A=2 and B=4
32=AxB^2 [32=2x4^2]
128=AxB^3 [128=2x4^3]
Answer:
No it will not cause it is different lengths and a square has all the same length plus i had this question before.
You have 1/4 divided by 2 which is the same as 1/4 divided by 2/1. First, find the reciprocal of 2/1 which is 1/2. You now have the problem 1/4 x 1/2. Multiple across.
