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Daniel [21]
4 years ago
5

a line passes through the points (14,5) and (19,15) determine and equation for a perpendicular line that passes through the poin

t (19,15)
Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
8 0
The equation of the line thru <span> (14,5) and (19,15)  is found as follows:

                      15-5           5
slope = m = ----------- = ------ = -1
                       19-14         5

Thus, the slope of any line perpendicular to this first line has the slope

m = -1/1 = -1.

Then, using the point-slope form, y-15 = -1(x-19), or y -15 = -x + 19, or
y= -x + 34 (answer)</span>
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Find the surface area of the surface given by the portion of the paraboloid z=3x2+3y2 that lies inside the cylinder x2+y2=4. (hi
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Parameterize the part of the paraboloid within the cylinder - I'll call it S - by

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\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=2}\int_{v=0}^{v=2\pi}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du\,\mathrm dv
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Take w=1+36u^2 so that \mathrm dw=72u\,\mathrm du, and the integral becomes

=\displaystyle\frac{2\pi}{72}\int_{w=1}^{w=145}\sqrt w\,\mathrm dw
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