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topjm [15]
4 years ago
11

( i put the directions) Helpp me graph thesse on a scatter plot sooo confused eee!! @musiclover helpp plzz lol

Mathematics
1 answer:
Liono4ka [1.6K]4 years ago
7 0
Make a chart with the humidity across the bottom ( X-Axis) and label it from 0 to 90, in increments of 10, ( 0, 10, 20, 30, 40, 50 , 60 , 70 , 80 , 90)

then use the temperature for the Y axis and label it from 0 to 14 ( 0, 2, 4, 6, 8, 10, 12, 14
 them make a dot where the humidity and temperature meet for each line, the first one would be (81, 8.7) and so on.

See attached picture:

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juin [17]
8/40 is equal to 20%-students

5/10 is equal to 50%- teachers
6 0
3 years ago
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Plz help i will mark brainliest
Rama09 [41]

Answer:

22 units

Step-by-step explanation:

The perimeter of a rectangle is 2(width + length)

In this case width = 2z + 2 and length = 3z + 3

replacing everything known:

110 = 2(2z + 2 + 3z + 3)

110/2 = (5z + 5)

55 = 5z + 5

55 - 5 = 5z

50 = 5z

10 = z

Segment PQ is the same as SR = 2z + 2

Replacing z = 10

PQ = 2(10) + 2

8 0
3 years ago
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If a= -9 and b= -4, what is the value of a + b?
Anna007 [38]

Answer:

-13

Step-by-step explanation:

a=-9 and b= -4

-9 + -4=

-13

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4 years ago
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Find both the number of combinations and the number of permutations for the given number of objects.
Nikitich [7]

Answer:

First, if we have a set of K elements, such that are ordered as:

{x₁, x₂, ...}

The total number of permutations for the K elements can be found in the next way.

For the first element in the set, we have K options.

For the second element in the set, we have (K - 1) options (because we already choose one)

For the third element we have (K - 2) options, and so on.

The total number of permutation is equal to the product between the numbers of options for each position's element, then the number of permutations for K elements is:

permutations = K*(K - 1)*(K - 2)*....*2*1 = K!

Now suppose that we have a set of N elements, and we want to make groups of K elements.

The total number of different combinations of K elements is given by the equation:

C(N, K) = \frac{N!}{(N - K)!*K!}

In this case we have 15 objects (then  N = 15) and we take 7 at the time (Then K = 7)

Where we need to take in account the number of combinations and also the permutations for each combination.

Then the total number of different sets is:

C(15*7)*7!

First, the total number of combinations will be:

C(15,7) = \frac{15!}{(15 - 7)!7!} = \frac{15!}{8!*7!}  = \frac{15*14*13*12*11*10*9}{7*6*5*4*3*2*1}  = 6,435

So we have 6,436 combinations, and each one of these combinations has 7! permutations.

permutations = 7! = 7*6*5*4*3*2*1 = 5,040

if we combine these we get:

Combinations*Permutations = 6,435*5,040 = 32,432,400

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3 years ago
Which of the following is not a way to represent the solution of the inequality
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