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Cerrena [4.2K]
3 years ago
6

What three digits are in the units period 4,083,817

Mathematics
1 answer:
viktelen [127]3 years ago
6 0
<span>In the given number : 4 083 817. Find the 3 digit which is placed in the unit period.
=> The unit period is the digit that is placed in the ones place of the number or the first digit on the right.
=> 7 is the unit period
=> 3 is the another unit period
=> 4 is the another unit period.
Thus, 4, 3 and 7 are the 3 digits placed in the unit period of the given number.</span><span>

</span>



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Ishaan is 333 times as old as christopher and is also 141414 years older than christopher.
GalinKa [24]
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3 years ago
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Charra [1.4K]

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However if the domain is restricted to -90° ≤ x ≤ 90°

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7 0
3 years ago
The vector ab has a magnitude of 20 units and is parallel to the<br> vector 4i + 3j.<br> find ab.
stepladder [879]

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j. Hence, The vector AB is 16i + 12j.

<h3>How to find the vector?</h3>

If we have given a vector v of initial point A and terminal point B

v = ai + bj

then the components form as;

AB = xi + yj

Here, xi and yj are the components of the vector.

Given;

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j.

magnitude

\sqrt{4^2 + 3^2} \\\\\sqrt{16 + 9} \\\\= 5

Unit vector in direction of resultant = (4i + 3j) / 5

Vector of magnitude 20 unit in direction of the resultant

= 20  x (4i + 3j) / 5

= 4 x (4i + 3j)

= 16i + 12j

Hence, The vector AB is 16i + 12j.

Learn more about vectors;

brainly.com/question/12500691

#SPJ1

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Answer:

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Step-by-step explanation:

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