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Cerrena [4.2K]
3 years ago
6

What three digits are in the units period 4,083,817

Mathematics
1 answer:
viktelen [127]3 years ago
6 0
<span>In the given number : 4 083 817. Find the 3 digit which is placed in the unit period.
=> The unit period is the digit that is placed in the ones place of the number or the first digit on the right.
=> 7 is the unit period
=> 3 is the another unit period
=> 4 is the another unit period.
Thus, 4, 3 and 7 are the 3 digits placed in the unit period of the given number.</span><span>

</span>



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Answer:

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The distance between point (x1,y1) and (x2,y2) on a coordinate plane is given by expression \sqrt{(x1-x2)^2+(y1-y2)^2}

In the problem given coordinate points are

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distance = \sqrt{(x1-x2)^2+(y1-y2)^2}\\=>distance = \sqrt{(0-a)^2+(a-0)^2}\\=>distance = \sqrt{(a)^2+(a)^2}\\\\=>distance = \sqrt{2a^2}\\=>distance = \sqrt{2} a

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The balance is in equilibrium, so the weights of the two sides are equal.

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