Is the following statement true or false? A line is zero-dimensional. true false

2 answers:

7 0

Answer:
False

Explanation:
Zero-dimensional would be a point.
One-Dimensional would be a line.
Two-Dimensional would be a plane.
Three-Dimensional would be a shape.

Vadim26 [7]3 years ago

3 0

False.
A single point on its own has dimension zero. A line has dimension one

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Q10. Consider the following algorithm:

maw [93]

Answer:

61,940

Step-by-step explanation:

For a recursive sequence of reasonable length, it is convenient to use a suitable calculator for figuring the terms of it. Since each term not only depends on previous terms, but also depends on the term number, it works well to use a spreadsheet for doing the calculations. The formula is easily entered and replicated for as many terms as may be required.

The result of executing the given algorithm is shown in the attachment. (We have assumed that g_1 means g[-1], and that g_2 means g[-2]. These are the starting values required to compute g[0] when k=0.

That calculation looks like ...

g[0] = (0 -1)×g[-1] +g[-2} = (-1)(9) +5 = -4

The attachment shows the last term (for k=8) is 61,940.

8 0

3 years ago

Can u help me ASAP. i need to know how to do it step by step

12345 [234]

Answer:

19

Step-by-step explanation:

$f(x) =4x^3-8x^2+ax+b$ has a factor $2x-1$ and

when divided by $x+2$ , remainder is 20.

To find:Remainder when divided by (x-1) ?

Solution:

$2x-1$ is a factor

$2x - 1 = 0 \Rightarrow x = \frac{1}{2}$ when we put this value of x to the function, it will become 0.

i.e.

$\Rightarrow f(\dfrac{1}{2}) =0 =4\times (\dfrac{1}2)^3-8(\dfrac{1}2)^2+\dfrac{a}{2}+b=0\\\Rightarrow \dfrac{1}{2}-2+\dfrac{a}{2}+b=0\\\Rightarrow 1-4+a+2b=0\\\Rightarrow a +2b=3 ......(1)$