Answer:

Step-by-step explanation:
Consider the given differential equation is



Taking all variables on right sides.


Let as assume,
and 
Find partial derivatives
and 
and 
Since
, therefore the given differential equation is exact.
The solution of the exact differential equation is






Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
Answer:
29.3 cm
Step-by-step explanation:
converting 70 degrees into radians, we get=(7/18)×π
now we know,
length of the arc= {(7/18)×π} × 24 (radius of the circle)
= 29.3 cm
Answer:
100
Step-by-step explanation:
because 4, 3, and 2 all make 180 and 4 and 2 are both 40 so you add that which makes 80 and then you take 180 and subtract 80 which gives you 100
Answer:
{t|60 <= t <= 85}
Step-by-step explanation:
The temperatures were measures at different times, but does not stop the values being real numbers (i.e. not discrete, or integer values).
So the range of the function is the set of all values between the minimum and maximum measured during the measuring interval (domain) of hours two and twenty-two.
The minimum value = 60F
The maximum value = 85F
So the interval of the range is [60,85], in interval notation.
In set-builder notation, it is
{t|60 <= t <= 85}