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Solution:
Area of parallelogram
= b × h
= 20 × 16
= 320 in^2
Area of triangle
= 1/2 × 20 × 8
= 80 in^2
Area of figure
= 320 + 80
= 400 in^2
Answer:
Option B is right
Step-by-step explanation:
We have in a triangle there are some properties inherent.
One is the perpendicular bisectors of all sides are concurrent.
These three concur at a point called the circumcentre of the triangle.
When we draw perpendicular bisector for a side AB, we get that all points on the perpendicular bisector are equidistance from A and B.
When we take the point of intersection of perpendicular bisector of AB and BC, we have the intersecting point S(say) is equidistant from A and B and also from B and C
In short this is equidistant from all 3 vertices and hence is centre of circumcicle of triangle ABC
Answer:
47.32 in^2
Step-by-step explanation:
Area rectangle = 21cm * 10.5cm = 220.5 cm^2
Area circle = pi*r^2
= Pi * 5.25^2
=( 86.59 in^2 )*2
= 173.18 in^2
Shaded region. 220.5 - 173.18 = 47.32 in^2