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Mashutka [201]
3 years ago
11

What is the scale factor of this dilation? Triangle A B C. Side A C is 8, C B is 10, A B is 6. Triangle A prime B prime C prime.

Side A prime C prime is 4, C prime B prime is 5, B prime A prime is 3. One-fifth One-half 1 2 PLZ HELP IM TIMMEDDDDD
Mathematics
2 answers:
jeka943 years ago
8 0

Answer:b

Step-by-step explanation:

blagie [28]3 years ago
5 0

Answer:

Step-by-step explanation:

Answer b

Ramadan Mübarek

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Find the degree of the monomial 7x^7 y^3
KengaRu [80]
I believe the answer is 7 but I’m 99% sure ,
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3 years ago
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Water flows from a tank with a rectangular base measuring 80cm by 70cm into another tank with a squarebase of side 60cm. If the
defon

Answer:

70cm

Step-by-step explanation:

,

Since, both of the tank posses the same quantity of water then there volume is the same thing

For rectangular base

Volume= (Lenght × breadth × hheight)

If we substitute values

Lenght= 80 cm

Breadth= 70 cm

height= 45 cm

Volume= 80cm × 70cm × 45cm

Volume= 252000cm^3

For square base

Volume= (side)^2 × height

side =60cm.

But volume of square base= volume of

rectangular base

252000cm^3= 60^2 × height

Height= (252000cm^3)/(60^2 )

Height= 70 cm

Hence, the second tank is 70 cm deep

4 0
3 years ago
Find the distance between A (6, -1) and B ( -18, 15)
timama [110]

Answer:

8√13 units

Step-by-step explanation:

We use the distance formula.

The distance formula states that the distance between two points (x, y) and (a, b) is equal to:

d = \sqrt{(x-a)^2+(y-b)^2}

Here, x = 6, y = -1, a = -18, and b = 15. Plug these in:

d = \sqrt{(x-a)^2+(y-b)^2}

d = \sqrt{(6-(-18))^2+(-1-15)^2}=\sqrt{24^2+(-16)^2} =\sqrt{576 + 256} =\sqrt{832} = 8√13

The answer is thus 8√13 units.

<em>~ an aesthetics lover</em>

7 0
4 years ago
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1/2(8a+200b)<br><br> Is the answer 4a+100b?
kaheart [24]

Answer:

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Step-by-step explanation:

4 0
2 years ago
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A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit
m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0
3 years ago
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