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3 years ago

1, 3,4,5,11, answer is 65 _ + (_-_)^2 +_x_

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

5 0

Answer:

1 + (11-4)^2 +3x5

Step-by-step explanation:

1 + (11-4)^2 +3x5

1 + (7)^2 + 3 x 5

1 + 49 + 15

50 + 15 = 65

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If a woman takes an early pregnancy test, she will either test positive, meaning that the test says she is pregnant, or test neg

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Answer:

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3 years ago

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4 years ago

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3 years ago

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4 years ago

The American Community Survey showed that residents of New York City have the longest travel times to get to work compared to re

LiRa [457]

Answer:

The probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

Step-by-step explanation:

The random variable X can be defined as the travel times to get to work.

The expected travel time is, μ = 38.3 minutes.

The distribution of random variable X can be defined as the distribution of time interval between which a person reaches their work place at a constant average rate.

This implies that X follows an Exponential distribution with parameter, $\lambda=\frac{1}{\mu}=\frac{1}{38.3}$ .

The probability density function of X is:

$f_{X}(x)=\lambda e^{-\lambda x};\ x\geq 0$

Compute the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work as follows:

$P(17.24\leq X\leq 42.13)=\int\limits^{42.13}_{17.24}{\frac{1}{38.3} e^{-x/38.3}}}\, dx$

$=\frac{1}{38.3}\times \int\limits^{42.13}_{17.24}{ e^{-x/38.3}}}\, dx$

$=\frac{1}{38.3}\times| \frac{e^{-x/38.3}}{-1/38.3}}|^{42.13}_{17.24}\\$

$=-e^{42.13/38.3}+e^{17.34/38.3}\\=-0.3329+0.6375\\=0.3046$

Thus, the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

6 0

3 years ago