Answer:
t=14
v=13
q=12
s=23
w=-4
x=28
Step-by-step explanation:
we know that the universal set =100
so, everything in it must add up to 100
first, from the information given to us,
t= n(A n C)= 14
v=n(B n C)= 13
to find q
we know from our guide that n(A) =40
which means everything inside A will add up to 40
therefore,
q + 7 + 7 + t = 40
and we already know that t = 14
so, that will be;
q + 7 + 7 + 14 = 40
therefore, q = 12
to find s,
we all know that n(B) = 50
which means that everything inside B will be equal to 50
therefore,
s + 7 + 7 + v = 50
and we know that v = 13
therefore,
s + 7 + 7 + 13 = 50
and s will end up to be = 23
to find w,
we know that n(C) = 30
so, everything in C end up to be all equal to 30
therefore,
t + 7 + w + v = 30
from our solution, t = 14, v = 13
so,
14 + 7 + w
Answer:
StartFraction 7 over 2 EndFraction can be used to find the unit rate if one divides 7 by 2 and compares the result to 1
Step-by-step explanation:
we know that
The formula to calculate the slope between two points is equal to
we have the points
B(2, 7) and D(4, 14)
substitute the values
The unit rate is
therefore
StartFraction 7 over 2 EndFraction can be used to find the unit rate if one divides 7 by 2 and compares the result to 1
Step-by-step explanation:
Answer:
Step-by-step explanation:
out of 180 you take out 140 so you get 40' for x and its a right triangle so out of 180-40' and 90' you will get 180-130=50' for y
Answer:
42 divided by 6=7 so 7 hrs
Step-by-step explanation:
its probalay wrong im not smart lol
Given:
The given equation is:
A line is perpendicular to the given line and passes through the point (4,-1).
To find:
The equation of required line.
Solution:
The slope intercept form of a line is:
Where, m is slope and b is y-intercept.
We have,
Here, the slope of the line is -4 and the y-intercept is 3.
Let the slope of required line be m.
We know that the product of slopes of two perpendicular lines is -1. So,
The slope of required line is and it passes through the point (4,-1). So, the equation of the line is:
Therefore, the equation of the required line is .
