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Black_prince [1.1K]
3 years ago
8

What is the point in the middle of a circle called?

Mathematics
2 answers:
irinina [24]3 years ago
8 0

The answer to this question is B. The center! [apex]

Rus_ich [418]3 years ago
3 0
The answer is b. Center
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Please help I dont understand
Anastasy [175]

Answer:

Angle 2=160

Angle 3=10

Step-by-step explanation:

The rhombus is made up of two isoceles triangle.

Angle 1 measures 160.

Since the triangle is a isoceles triangle, the opposite angles of the congruent sides is equal angles to each other.

So the reamaing angles in the top triangle are equal so we can use this equation

Remeber that triangle maximum degree it can hold is 180

160 + x + x = 180

160 + 2x = 180

2x = 20

x = 10

We have two congruent triangle side they share Three sides. SSS

This means the corresponding angle of Angle 1 is Angle 2.

Angle 2=Angle 1 by CPCTC.

Angle 2=160

Angle 3 corresponds with one of the remaining congruent angles so it measures

10.

8 0
3 years ago
Pls help I need it by 11:59
chubhunter [2.5K]

no se por que veo esto jaja

8 0
3 years ago
Need answer quick and simple explanation
harkovskaia [24]
(x + 2)(x + 2)(x + 2)
(x^2 + 4x + 4)(x + 2)
x^3 + 4x^2 + 4x + 2x^2 + 8x + 8
Simplify
Solution: x^3 + 6x^2 + 12x + 8
The answer is A

5 0
3 years ago
Read 2 more answers
The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =
avanturin [10]
Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
            b = 1
            c = 5

The discriminate b^2 - 4ac = 41

To solve for the zeros of the quadratic function, use this formula:

x = ( -b +-√ (b^2 - 4ac) ) / 2a

x = ( 1 + √41 ) / 4  or 1.85
x = ( 1 - √41 ) / 4  or -1.35

Therefore, the zeros of the quadratic equation are 1.85 and -1.35. 
4 0
3 years ago
Read 2 more answers
Hi, I need help with another problem. (Solve for x)
NARA [144]

Answer:

x = 2

Step-by-step explanation:

x/(x+1) = (x+6) / (x+10)

the 10 comes from 9+1

Then cross multiply and solve for x

the terms cancel out just leaving behind a nice linear function.

5 0
3 years ago
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