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konstantin123 [22]

3 years ago

10

What is the value of h(−2) when h(x)=3x+1 ?

1 answer:

scoray [572]3 years ago

3 0

All you have to do is plug in the given number into the equation
h(x)=3x+1
h(x)=3(-2)+1
h(x)=-6+1
h(x)= -5

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Solution of this equation

lara31 [8.8K]

2.5y + 3x = 27
5x - 2.5y = 5

Align the variables to make solving this easier.

2.5y + 3x = 27
-2.5y + 5x = 5

You can see that the 2.5y and -2.5y cancel each other out. Then add the 3x and 5x, and 27 + 5.

3x = 27
5x = 5

8x = 32

Divide both sides by 8.

x = 4

Now input that x into one of the equations to get y.

2.5y + 3(4) = 27
2.5y + 12 = 27
2.5y = 15
y = 6

The answer to this system of equations is x = 4, y = 6. (4, 6)

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