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Licemer1 [7]
3 years ago
11

What methods could you use to calculate the x-coordinate of the midpoint of a horizontal segment with the endpoints of (-20, 0)

and (20, 0)?. . A. divide 0 by 20 . B. calculate the average of the x-coordinates . C. divide 20 by 2 . D. divide 2 by 20 . E. take the average of the endpoints .
Mathematics
2 answers:
Ronch [10]3 years ago
7 0
The coordinates (abscissa and ordinates) of the midpoint of the line segment is the average of the abscissas and the ordinates, respectively. Therefore, the x - coordinate of the midpoint is equal to -20 + 20 or 0 by 2 which is zero. The answer is letter E. 
marta [7]3 years ago
7 0

Answer:

Option B is correct .

Step-by-step explanation:

Consider the line segment joining points A\left ( x_1,y_1 \right )\,,\,B\left ( x_2,y_2 \right ) . It's midpoint is given by \left ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right ) .

Midpoint is basically the centre point of a line segment .

Here, given points are \left ( -20,0 \right )\,,\,\left ( 20,0 \right ) .

Consider the following:

\left ( x_1,y_1 \right )=\left ( -20,0 \right )\\\left ( x_2,y_2 \right )=\left ( 20,0 \right )

To find: x-coordinate of the midpoint of a horizontal segment with the endpoints (-20,0) , (20,0) .

Solution:

x-coordinate = \frac{x_1+x_2}{2}

On putting x_1=-20\,,\,x_2=20 , we get

x - coordinate = \frac{-20+20}{2}=0

So, here we calculate the average of x-coordinates .

Option B is correct .

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vesna_86 [32]

So, values of x are: x=2\sqrt{15},\,\,x=-2\sqrt{15}

Step-by-step explanation:

We need to find the square root of 5x^2 = 300

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So, values of x are: x=2\sqrt{15},\,\,x=-2\sqrt{15}

Keywords: Square root

Learn more about square root at:

  • brainly.com/question/3511750
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#learnwithBrainly

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