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iren2701 [21]
3 years ago
5

FOR 15 POINTS I WILL GIVE BRAINLEST IF YOU ARE CORRECT! What is the solution to the system that is created by the equation y = 2

x + 10 and the graph shown below? On a coordinate plane, a line goes through (negative 2, 0) and (0, 2). (–8, –6) (–4, –2) (0, 2) (2, 4)

Mathematics
2 answers:
Arisa [49]3 years ago
8 0

Answer:

(-8,-6)

Step-by-step explanation:

This is the real answer for this question and this is a image of the graph

goblinko [34]3 years ago
6 0

The solution point is (4,2).

Step-by-step explanation:

Equation of straight line passing through the points (0,0) and (4,2) is given by

⇒ 2y = x ............ (1)

And the other straight line is y = - x + 6 .............. (2)

Now, solving equations (1) and (2) we get, y = - 2y + 6

⇒ 3y = 6

⇒ y = 2

And from equation (1) we get, x = 2y = 4

Therefore, the solution point is (4,2). (Answer)

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A rectangular lamina of uniform density is situated with opposite corners at (0,0) and (15,4). calculate its radii of gyration a
Sphinxa [80]
First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.


I_{x}= \int\limits^15_0\int\limits^4_0 {k y^{2} } \, dx  dy= \frac{1}{3}k (15-4)^4=4880.33k

I_{y}= \int\limits^15_0\int\limits^4_0 {k x^{2} } \, dx  dy= \frac{1}{3}k (15-4)^4=4880.33k

Then, the radii of gyration for

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where m = k(15-4)² = 121k. Then,

x = y = [4880.33k/121k] = 40.33

I hope I was able to help you. Have a good day.
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