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RoseWind [281]
2 years ago
5

How do you describe the principal square root of the 34? *

Mathematics
1 answer:
malfutka [58]2 years ago
5 0

Answer:

B. The square root of 34 is an irrational number.

Step-by-step explanation:

The square root of 34 is a rational number if 34 is a perfect square.

Since 34 is not a perfect square, it is an irrational number.

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Which fraction has the same value as 2 3<br> 8
Alik [6]

Answer:

The Answer : 19/8 Not sure if I'm correct

7 0
3 years ago
If 5-3(2a+1)=-4a+10, what is the value of a+2​
AlekseyPX

Answer:

-2

<em>BRAINLIEST, PLEASE!</em>

Step-by-step explanation:

5 - 3(2a + 1) = -4a + 10

5 - 6a - 3 = -4a + 10

2 - 6a = -4a + 10

-2a = 8

a = -4

-4 + 2 = -2

5 0
3 years ago
Read 2 more answers
If you borrow $675 for six years at a interest rate of 10% how much interest will you pay
murzikaleks [220]

Answer:

the answer is $40.5

Step-by-step explanation:

the basic formula of finding our interest is I = PxRxT

P (principal) = 675

R (rate) = 10%  (we have to turn it into a decimal which is 0.010)

T (time) = 6 years

so :

I = 675 x 0.010 x 6

I = 40.5


7 0
3 years ago
The product of a number and -3, increased by 8, is 20
natita [175]

answer:

-4

Step-by-step explanation:

-3x+8= 20

-8 -8

-3x = 12

÷-3. = ÷-3

x = -4

3 0
3 years ago
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
3 years ago
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