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tensa zangetsu [6.8K]
3 years ago
13

In a group of 100 adults, 70 say they are most likely to do spring houseclean-ing in March, April, or May. Of these 70, the numb

er who clean in April is 14 more than the total number who clean in March and May. The total number who clean in April and May is 2 more than three times the number who clean in March.
Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

Adults that clean in March = 18

Adults that clean in April = 48

Adults that clean in May = 4

Step-by-step explanation:

Adults that clean in the months of March, April and May = 70

Let a represent March, b represent April and c represent May.

Therefore, a + b + c = 70     (i)

From the question, the number of adults that clean in April is 14 more than number of the adults cleaning in months of March and May combined.

b - ( a + c) = 14      (ii)

also, the total number who clean in April and May is 2 more than three times the number who clean in March.

b + c - 3a = 2     (iii)

From (i), a + c =   70 - b (iv)

Substituting (iv) into (ii), b - ( 70 - b) = 14

b -70 + b = 14

2b = 84, b =48

Therefore a + c = 70 - 48

a + c = 22; c = 22 - a   (v)

Substituting (v) and b = 48 into (iii)

48 + 22 - a -3a = 2

4a = 72, a = 18

Therefore, c = 22 - 18

c = 4

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Ipatiy [6.2K]

Answer:

360 divided by 12 is 30 because 12 times 30 is 360

Step-by-step explanation:

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3 years ago
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Si el velocimetro de un auto marca un 25% mas que la verdadera velocidad y en este momento marca 100km/h entonces la velocidad v
GenaCL600 [577]

Answer:

True speed of the car is 87 km/h.

Step-by-step explanation:

Speed = 100 km/h

hike in speed = 25 %

Let the true speed is v.

v + 15% of v = 100 \\\\v + 0.15 v = 100 \\\\1.5 v = 100\\\\ v = 87  km/h

6 0
3 years ago
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
All three please 10 points
GaryK [48]

Answer:

A) x = 3 or -1

B) x = -7

C)x = -7

Step-by-step explanation:

A) x² + 2x + 1 = 2x² - 2

Rearranging, we have;

2x² - x² - 2x - 2 - 1 = 0

x² - 2x - 3 = 0

Using quadratic formula, we have;

x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

x = (2 ± √16)/2

x = (2 + 4)/2 or (2 - 4)/2

x = 6/2 or -2/2

x = 3 or -1

B) ((x + 2)/3) - 2/15 = (x - 2)/5

Multiply through by 15 to get;

5(x + 2) - 2 = 3(x - 2)

5x + 10 - 2 = 3x - 6

5x - 3x = -6 - 10 + 2

2x = -14

x = -14/2

x = -7

C) log(2x + 3) = 2log x

From log derivations, 2 log x is same as log x²

Thus;

log(2x + 3) = logx²

Log will cancel out to give;

2x + 3 = x²

x² - 2x - 3 = 0

Using quadratic formula, we have;

x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

x = (2 ± √16)/2

x = (2 + 4)/2 or (2 - 4)/2

x = 6/2 or -2/2

x = 3 or -1

5 0
3 years ago
Rewrite the expression with a perfect square: x^2 - 14x + 11
nikitadnepr [17]

   Factoring  x2-14x+11 

The first term is,  x2  its coefficient is  1 .

The middle term is,  -14x  its coefficient is  -14 .

The last term, "the constant", is  +11 

Step-1 : Multiply the coefficient of the first term by the constant   1 • 11 = 11 

Step-2 : Find two factors of  11  whose sum equals the coefficient of the middle term, which is   -14 .

     -11   +   -1   =   -12     -1   +   -11   =   -12     1   +   11   =   12     11   +   1   =   12

Observation : No two such factors can be found

4 0
3 years ago
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