All categories

3 years ago

A company is analyzing monthly data for the number of cars sold

Mathematics

1 answer:

CaHeK987 [17]3 years ago

8 0

wheres the rest of the question?

You might be interested in

Find the complex zeros of the following polynomial function.

GalinKa [24]

Answer:

$x=\frac{-1\pm\sqrt{3}i}{2}$

Step-by-step explanation:

$f(x)=x^3-1$

$0=x^3-1$

$0=(x^2+2x+1)(x-1)$

$x-1=0$

$x=1$ <-- Real Solution

$x^2+x+1=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-2\pm\sqrt{2^2-4(1)(1)}}{2(1)}$

$x=\frac{-1\pm\sqrt{1^2-4(1)(1)}}{2(1)}$

$x=\frac{-1\pm\sqrt{1-4}}{2}$

$x=\frac{-1\pm\sqrt{-3}}{2}$

$x=\frac{-1\pm\sqrt{3}i}{2}$ <-- Complex Solutions

6 0

2 years ago

Please help me with this question and can u please do it on paper and take a pic of it. Thank You!

Likurg_2 [28]

click on pics click on pics

GodBless c:

4 0

3 years ago

What is the constant(K)?

s344n2d4d5 [400]

Answer:

a (5)

Step-by-step explanation:

The constant is the same as y/x in a proportional relationship

8 0

3 years ago

Solve for x using cross multiplication 2x + 1 = x+5 2x + 1 3 x = [?]

jonny [76]

Step-by-step explanation:

$\frac{2x + 1}{3} = \frac{x + 5}{2} \\ 2(2x + 1) = 3(x + 5) \\ \: \: \: \: 4x + 2 = 3x + 15 \\ 4x - 3x = 15 - 2 \: \\ \: \: \: x = 13$

8 0

2 years ago

The domain of the following relation: R {(6, -2), (1, 2), (-3, -4), (-3, 2)} is

monitta

The domain is the set of possible inputs, i.e. the x-coordinates of the points.

Here those are 6, 1 and - 3 which in order is -3, 1, 6.

Then the answer is {-3, 1, 6}.

By the way note that this relation is not a function. Do you know why?

Because the image of -3 is not stated unambiguosly.

5 0

2 years ago