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alex41 [277]
3 years ago
8

a contractor was hired to remodel a kitchen. she can complete 3/8 of the kitchen remodeling project in one day. how much of the

kitchen is left to remodel after two days?
Mathematics
2 answers:
vovangra [49]3 years ago
8 0
She would have 5/8 days left
AlladinOne [14]3 years ago
4 0
Nothing. The improper fraction for what she has done could be 9/8.
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What is the correct expanded form for the number 43.205?
nasty-shy [4]

Answer:

2nd one

Step-by-step explanation:

5 0
2 years ago
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QUESTIONS
Alika [10]

Answer:

A) 2 cups

Step-by-step explanation:

For every 1 batch you need 1/3 so when you multiply the number of batches by 6 you need to do the same for the cups of raisins.

1/3 x 6 = 1/3 x 6/1 = 6/3 = 2

5 0
2 years ago
18 cajas de manzanas y peras fueron llevadas a la escuela. Las peras trajeron 210 kg en 6 cajas. ¿Cuántos kilos de manzanas fuer
Katyanochek1 [597]

Answer:

504 kilos de manzanas fueron llevados a la escuela.

Step-by-step explanation:

Sean x, y la cantidad de cajas de manzanas y peras, respectivamente. De acuerdo con el enunciado, tenemos el siguiente sistema de ecuaciones:

Total de cajas

x+y = 18 (1)

Masa de cada caja de peras

y\cdot m_{P} = 210 (2)

y = 6 (3)

Masa de caja de manzanas

m_{M} = m_{P}+7 (4)

De (2) en (3), tenemos que la masa de cada caja de peras es:

m_{P} = 35\,kg

Por (4), encontramos que la masa de cada caja de manzanas es:

m_{M} = 35\,kg+7\,kg

m_{M} = 42\,kg

Finalmente, de (1) tenemos la cantidad de cajas de manzana:

x = 18-y

x = 12

La cantidad de kilos de manzanas llevada a la escuela se obtiene al multiplicar la cantidad de cajas de manzana por la masa de cada caja:

M = (12)\cdot (42\,kg)

M = 504\,kg

504 kilos de manzanas fueron llevados a la escuela.

7 0
2 years ago
Solve the equation by completing the square. Round the square. Round to the nearest hundredth if necessary. x2 - 3x -12 =0
dmitriy555 [2]
A:5.27,-2.27 should be your answer
5 0
3 years ago
Help please!!!! it makes so sense
Tamiku [17]

Answer:

(- \frac{1}{5} , 0 )

Step-by-step explanation:

to find where the line crosses the x- axis, let y = 0 in the equation and solve for x

5x - 2(0) + 1 = 0

5x - 0 + 1 = 0

5x + 1 = 0 ( subtract 1 from both sides )

5x = - 1 ( divide both sides by 5 )

x = - \frac{1}{5}

the line crosses the x- axis at (- \frac{1}{5}, 0 ) or ( - 0.2, 0 )

4 0
2 years ago
Read 2 more answers
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