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Elena-2011 [213]
3 years ago
9

The probability that a given urine sample analyzed in a pathology lab contains protein is 0.73 (event A). The probability that t

he urine sample contains the protein albumin is 0.58 (event B).
Event A: The sample contains protein.Event B: The sample contains the protein albumin.
The probability that a sample contains protein and that the protein is albumin is 0.58. Which statement is true?
A.Events A and B are dependent because P(A and B) P(A) + P(B).
B.Events A and B are dependent because P(A and B) = P(A) + P(B).
C.Events A and B are dependent because P(A and B) = P(A)P(B).
D.Events A and B are dependent because P(A and B)     P(A)      P(B).
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
Event\ A\ and\ event\ B\ are\  independent\\\\ \ \Leftrightarrow\ \ \ \ P(A\ \cap\ B)=P(A)\ \cdot\ P(B)\\---------------------\\\\P(A)=0.78\ \ \ and\ \ \ P(B)=0.58\ \ \ and\ \ \ P(A\ \cap\ B)=0.58\\\\P(A)\cdot P(B)=0.78\cdot0.58\  \neq \ 0.58\\\\\Rightarrow\ \ \ Event\ A\ and\ event\ B\ are\  dependent\ \ \ \Rightarrow\ \ \ Ans.\ (?)
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Given A(0,-4), B(0,-9), and C(-2,-5). Find the length of BC.
Ivan

Answer:

4.5

Step-by-step explanation:

B(0,-9)

C(-2,-5)

=> BC = \sqrt{(-2-0)^{2} -(-5+9)^{2} }  = 4.4721

5 0
3 years ago
What is the value of q?
malfutka [58]
Triangles QST and RST are similar.  Therefore, the following is true:

 q       s
--- = ----   This results in 10q=rs.
 r      10

Also, since RST is a right triangle, 4^2 + s^2 = q^2.
Since QST is also a right triangle, s^2 + 10^2 = r^2.  
            4      s
Also:  ---- = -----    which leads to s^2 = 40
            s      10

Because of this, 4^2 + s^2 = q^2 becomes 16 + 40 = 56 = q^2

Then q = sqrt(56) = sqrt(4)*sqrt(14) = 2*sqrt(14) (answer)


5 0
3 years ago
Read 2 more answers
3x=-5y<br> 6x-7y=17 <br> Solve the equation
love history [14]
3x = -5y -------------- (1)
6x - 7y = 17 --------- (2)

From (1):
3x = -5y
x = -5/3 y ---------- sub into (2)

6 (-5/3 y) - 7y = 17
-10y - 7y = 17
-17y = 17
y = -1 ------------ Sub into (1)
3x = -5 (-1)
3x = 5
x = 5/3

Ans: x = 5/3, y = -1

7 0
3 years ago
Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
virgil has 1/6 of a bday cake left over. he wants to share with 3 friends. what fraction of the original cake will each of the f
Tpy6a [65]
1/6 divided by 4 = 1/24
so each person would get 1/24 of that cake
(just wondering what would the flavor of the cake be??)
3 0
3 years ago
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