Answer:
25
Step-by-step explanation:
Let n be the first integer.
Then the second integer will be (n + 1).
And the third will be (n + 2).
The sum is 78. Therefore:
Solve for n. Combine like terms:
So:
Therefore:
Therefore, the first integer is 25.
So our sequene is 25, 26, and 27.
The integer closest to zero will thus be 25.
Answer:
the answer is 24x..
Step-by-step explanation:
you just have to add the numbers ....
Yes, if you solve both problems they come out to the same answer.
Answer:
(-3,-4)
Step-by-step explanation:
You draw it...
So since we are reflecting across the x-axis, we want the x-coordinate to stay the same. We just need to take the opposite of y.
Ans. (-3,-4)
Answer:
First, let's define an arithmetic sequence:
In an arithmetic sequence, the difference between any two consecutive terms is always the same.
Then we can write it in a general way as:
aₙ = a₁ + (n - 1)*d
where:
aₙ is the n-th term of the sequence.
d is the constant difference between two consecutive terms.
a₁ is the initial term of our sequence.
Now in this case we know that the first terms of our sequence are:
84, 77, ...
Then we know the initial term of our sequence:
a₁ = 84.
And the value of d can be calculated as:
d = a₂ - a₁ = 77 - 84 = -7
Then the general way of writing this sequence is:
aₙ = 84 + (n - 1)*(-7)
And the recursion relation is:
aₙ = aₙ₋₁ - 7
So for the n-th term, we must subtract 7 of the previous term.
