Answer:
The percentage of her shots that will travel less than 180 yards is approximately 15.9%
Step-by-step explanation:
First it will be required to find the standard or z-score from the following formula

Where:
z = z or standard score
x = value that is observed = 180 yards
μ = Sample mean = 200 yards
σ = Sample standard deviation yards
Plugging the values, we have;

Therefore, the probability that her shots will travel less than 180 is given by the relation;
p( x < 180 yards) = p(z < -1) = 0.15866
Therefore, the percentage of her shots that will travel less than 180 = 0.15866 × 100
= 15.866% ≈ 15.9%.
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Step-by-step explanation:
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I believe the answer is:
2b x (b-3) x (b+3)
Answer:
67
Step-by-step explanation: