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Tresset [83]
3 years ago
15

Nonzero multiples of 16

Mathematics
1 answer:
Anna11 [10]3 years ago
8 0
2 just 2 thats it♥♥

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A lemonade recipe calls for 6 gallons of water how many quarts of water are needed for the recipe
lyudmila [28]

Answer:

24 quarts

Step-by-step explanation:

in one gallon there is 4 quarts so 6*4= 24

5 0
2 years ago
Read 2 more answers
Tay–Sachs Disease Tay–Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri
BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that p = 0.25

Three children:

This means that n = 3

Question a:

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

p = 0.75*0.75*0.25 = 0.1406

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0
3 years ago
Solve each equation for the specified variable 1.Y+V=W, solve for V
dmitriy555 [2]
<span>Y+V=W
     V = W - Y
hope that helps</span>
6 0
3 years ago
Complete this sequence 4.15, 6.3, 8.45
Scrat [10]
+2.15.
Explanation: subtract 6.3 by 4.15 = 2.15 so you add 2.15
8 0
2 years ago
Read 2 more answers
Find an equation for the line perpendicular to y= -4/3x+5 with​ y-intercept (0,-12). Write the answer in​ slope-intercept form
Arisa [49]

Answer:

y=3/4x−12.

Step-by-step explanation:

Slope of the perpendicular line is negative inverse: m=34.

The equation of the perpendicular line is y=3x4+a.

To find a, we use the fact that the line should pass through the given point: −12=(34)⋅(0)+a.

a=−12.

Therefore, the equation of the line is y=3x4−12.

If this helps you, please give bainliest!

4 0
2 years ago
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