Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
39 squares in all
Step-by-step explanation:
step 1 right it out
18-monday
7-tuesday
7-wednesday
7-thursday
Step 2 add them all up
then you get 39
hopes it help make me brainlist
Number 15 is c and number 16 is a
