The continuous change in position of an object relative to a point of reference is?

1 answer:

3 0

<span>The continuous change in position of an object relative to a point of reference is the object's trajectory.</span>

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Graph the function and answer each of the following questions, f(x) = -3x + 5

olga2289 [7]

A. 5
B. -3/1
C. Negative
D. You have to go down 3 over to the right one from where your y-intercept is.

To plot the y intercept plot (0,5)
To plot the next point go down 3 over 1 to the right from the y-ing

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2 years ago

Which number line represents the solution to the inequality 22 > 10x

S_A_V [24]

Answer:

$\large\boxed{x$

Step-by-step explanation:

$22>10x\qquad\text{divide both sides by 10}\\\\\dfrac{22}{10}>\dfrac{10x}{10}\\\\2.2>x\to\boxed{x$

<, > - open circle

≤, ≥ - closed circle

<, ≤ - draw the line to the left

>, ≥ - draw the line to the right

3 0

2 years ago

se an inequality symbol (<, >, =, ≠) to compare 5 + (−4) _____ 14 + (−13) A. > B. = C. ≠ D.

qwelly [4]

5+(-4)= 1
14+(-13)= 1
So the answer is B. =
I hope this helps

3 0

2 years ago

Read 2 more answers

Let f(x) = 1/x . Find the number b such that the average rate of change of f on the interval [2, b] is − 1/8

vekshin1

Answer:

b=4

Step-by-step explanation:

So, we have the function $f(x)=1/x$ . We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).

f(2) = 1/(2) = 1/2

So, we have the point (2, 1/2)

At point b, f(b) = 1/b.

Let's plug this into the slope formula:

$\frac{y_2-y_1}{x_2-x_1}=\frac{.5-\frac{1}{b} }{2-b} =-1/8$

Now, we just need to solve for b. First, let's multiply both the numerator and denominator by b (to get rid of the annoying fraction in the numerator).

$\frac{.5b-1}{2b-b^2} =\frac{-1}{8}$