3 years ago

The continuous change in position of an object relative to a point of reference is?

1 answer:

3 0

<span>The continuous change in position of an object relative to a point of reference is the object's trajectory.</span>

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Dmitrij [34]

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2 years ago

I do no understand this

vovangra [49]

The equation of a line for the given slope is $y=\frac{1}{2} x+1$ .

Solution:

Given data:

Slope (m) = $\frac{1}{2}$

Point = (–2, 0)

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<u>Point-slope formula:</u>

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3 years ago

Which expression is not equivalent to?

grigory [225]

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3 0

3 years ago

Witch of the following expression is equivalent to the logarithmic expression below. log(3)5/x^2

BabaBlast [244]

Assuing you mean
$log_{3}(\frac{5}{x^2})$
remember that $log(\frac{a}{b})=log(a)-log(b)$
also, $log(x^m)=(m)log(x)$

so
$log_{3}(\frac{5}{x^2})=$
$log_{3}(5)-log_{3}(x^2)=$
$log_{3}(5)-2log{3}(x)$

the answer is B

4 0

3 years ago

Read 2 more answers