Answer:
θ = 5π/6 rad and 11π/6 rad
Step-by-step explanation:
Given the expression cotθ+√3=0
Subtract √3 from both sides
cotθ+√3-√3=0-√3
cotθ = -√3
Since cotθ = 1/tanθ
1/tanθ = -√3
Reciprocate both sides:
tanθ = -1/√3
θ = tan^-1(-1/√3)
θ = -30°
Since the angle is negative, and tanθ is negative in the second and fourth quadrant.
In the second quadrant;
θ = 180-30
θ = 150°
Since 180° = πrad
150° = 150π/180
150° = 5π/6 rad
In the fourth quadrant;
θ = 360-30
θ = 330°
Since 180° = πrad
330° = 330π/180
330° = 11π/6 rad
Hence the solutions are 5π/6 rad and 11π/6 rad.
The distance formula is shown here. If you plug your coordinates into the formula, you will get d=square root of (5-3)^2+(8-10)^2 which equals 2.828
C
All u have to do is add 23.5 to 23.5
Answer:
a= d-r +c
Step-by-step explanation:
a-c = d-r
+c
a= d-r +c
9514 1404 393
Answer:
2√5
Step-by-step explanation:
The distance formula is useful for this.
d = √((x2 -x1)² +(y2 -y1)²)
d = √((2 -(-2))² +(1 -3)²) = √(4² +(-2)²) = √20
d = 2√5
The length of segment PQ is 2√5.
