linda earns $90,000 per year. if she does not work for 2 months in a year, how much money would she earn?

Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima

Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

$\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416$

3 0

3 years ago

Which relation is a function?

Doss [256]

Answer:

B

Step-by-step explanation:

All functions have y with a power of 1.

option B. is the only one where y has a power of 1.

5 0

3 years ago

Read 2 more answers

There is a 70% chance that your car will get stuck in the snow during the next big snow fall. Given that you are already stuck i

nikdorinn [45]

Answer:

63%

Step-by-step explanation:

This is a problem of conditional probability.

The two events that are given are:

Car stuck in the snow - Let it be event S. P(S) = 70% = 0.70
Require a tow truck - Let it be event T.

We have to find the probability of being stuck in the snow AND requiring a tow truck which can be given as P(S and T)

We are also given the conditional probability, which is P(T | S) = 90% = 0.90

Using the given formula for our case we can modify the formula as:

$P(T|S)=\frac{P(S \cap T)}{P(S)}$

$0.90=\frac{P(S \cap T)}{0.70}\\\\ P(S \cap T)=0.90 \times 0.70\\\\ P(S \cap T)=0.63$

Therefore, there is 63% (0.63) chance that you will get stuck in the snow with your car AND require a tow truck to pull you out

4 0

3 years ago

This bag has an unknown number of lollipops and jelly snakes in it. I know that Pr (jelly snake) = 4/5. How many jelly snakes co

juin [17]

Answer:

40.

Step-by-step explanation:

Let J represent jelly snake.

Let L represent lollipops

Let S represent sample space

Let y represent the number of jelly snake in the bag. I.e

Number of J = y

Number of L = 10

Number of S = 10 + y

From the question given, we were told that the probability of jelly snake P(J) is 4/5.

But probability of jelly snake, P(J) is given by:

P(J) = nJ/nS

nJ = y

nS = 10 + y

P(J) = 4/5

Thu, we can obtain the number jelly snake, y, in the bag as follow:

P(J) = nJ/nS

4/5 = y/(10 + y)

Cross multiply

5y = 4(10 + y)

Clear bracket

5y = 40 + 4y

Collect like terms

5y – 4y = 40

y = 40

Therefore, the number of jelly snake in the bag is 40

8 0

2 years ago

Refer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculato

Mariulka [41]

The mean of the dataset is the average, while the median is the middle element.

The mean and the median of the given dataset is 98.2
The results support the common belief that the mean body temperature is 98.6F

The mean of the dataset is calculated using:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{99.2+ 99.2 +98.2+............+97.7}{48}$

$\bar x = \frac{4715}{48}$

$\bar x = 98.2$

The median position is:

$Median = \frac{1}{2}(n + 1)$

$Median = \frac{1}{2}(48 + 1)$

$Median = \frac{1}{2}(49)$

$Median = 24.5$

This means that the median is the average of the 24th and 25th element

Using the sorted dataset, we have:

$Median = \frac{1}{2}(98.2 + 98.2)$

$Median = 98.2$

Because the calculated mean and the common belief (98.6) are close, then we can conclude that the results support the common belief that the mean body temperature is 98.6F