The final result is -2(3 - 2p).
The height of an object after it is released can be modeled by the function mc016-1.jpg, where t is the number of seconds after
2 answers:
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Answer:
m = - , c = -
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
2x + 3y + 1 = 0 ( subtract 2x + 1 from both sides )
3y = - 2x - 1 ( divide terms by 3 )
y = - x -
← in slope- intercept form
with m = - and c = -
Answer:
97.6% of the trees will have diameters between 7.6 and 18.6 inches.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 12 inches
Standard Deviation, σ = 2.2 inches
We are given that the distribution of diameter of tree is a mound shaped distribution that is a normal distribution.
Formula:
P(diameters between 7.6 and 18.6 inches)
97.6% of the trees will have diameters between 7.6 and 18.6 inches.
Answer:
Step-by-step explanation:
Given: 8x² + 10x - 7 = 0
<u>When factoring trinomials of the form ax² + bx + c</u>:
- multiply the leading coefficient and the last term.
- find the product factors that add to give you the coefficient of the middle term.
- rewrite the polynomial with those factors replacing the middle term.
1. Split the middle term:
⇒ 8 × -7 = -56 [multiply the leading coefficient and the last term]
⇒ 14, -4 [find the product factors that add to the middle term's coefficient]
⇒ 8x² + 14x - 4x - 7 = 0 [rewrite with those factors replacing the middle term.]
2. Factor by grouping:
⇒ 8x² + 14x - 4x - 7 = 0 [factor out 2x]
⇒ 2x(4x + 7) - 4x - 7 = 0 [factor out -1 or the negative sign]
⇒ 2x(4x + 7) -1(4x + 7) = 0 [factor out 4x + 7]
⟹ (4x + 7)(2x - 1) = 0
3. Separate into 2 cases:
- 4x + 7 = 0
- 2x - 1 = 0
<u><em>Case 1:</em></u>
⇒ 4x + 7 = 0 [subtract 7 from both sides]
⇒ 4x + 7 - 7 = 0 - 7
⇒ 4x = -7 [divide both sides by 4]
⇒ 4x ÷ 4 = -7 ÷ 4
⟹ x =
<u><em>Case 2:</em></u>
⇒ 2x - 1 = 0 [subtract 1 from both sides]
⇒ 2x - 1 + 1 = 0 + 1
⇒ 2x = 1 [divide both sides by 2]
⇒ 2x ÷ 2 = 1 ÷ 2
⟹ x =
Solutions:
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