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nekit [7.7K]
3 years ago
5

The height of an object after it is released can be modeled by the function mc016-1.jpg, where t is the number of seconds after

the object is released, v is the upward speed at release, and s is the starting height. If a quarterback throws a ball from his hand 6 feet in the air at a speed of 25 feet per second, how much time does his teammate have to catch the ball?
A)about 1.45 seconds
B)about 1.77 seconds
C)about 6 seconds
D)about 25 seconds
Mathematics
2 answers:
zzz [600]3 years ago
6 0
The correct answer is b.
Klio2033 [76]3 years ago
6 0
The answer is b
Hope this helps
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yeah

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2 years ago
I need help pretty please!
Naddika [18.5K]

Answer:

cos(z) = .3846153846 and angle z = 67.38°

Step-by-step explanation:

Side UV is corresponding to side YX.  Side VW is corresponding to side YZ.  Side UW is corresponding to side XZ.

Starting with the first corresponding pair, we are told that side UV is 36, and that side YX is 3/5 of that.  So side YX is

\frac{3}{5}*36=21.6

We are next told that side VW is 39, so side YZ is

\frac{3}{5}*39=23.4

In order to find the cos of angle z, we need the adjacent side, which is side XZ.  Side XZ is 3/5 of side UW.  Right now we don't know the length of side UW, so we find it using Pythagorean's Theorem:

39^2-36^2=UW^2 and

UW^2=225 so

UW = 15

Now we can say that side XZ is

\frac{3}{5}*15=9

The cos of an angle is the side adjacent to the angle (9) over the hypotenuse of the triangle (23.4) so our ratio is:

cos(z)=\frac{9}{23.4}

which divides to

cos(z) = .3846153846

If you need the value of the angle, use the inverse cosine function on your calculator in degree mode to find that

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3 0
2 years ago
The​ half-life of a certain tranquilizer in the bloodstream is 22 hours. How long will it take for the drug to decay to 90​% of
nasty-shy [4]

Answer:

It will take approximately 3.34 hours for the drug to decay to 90% of the original dosage

Step-by-step explanation:

As suggested, we use the formula for exponential decay:

A(t)=A_0\,e^{-k\,t}

From the given information, the half life of the drug in blood id 22 hours, so that means that it takes that number of hours to go from the initial value A_0, to a final value equal to A_0/2. Using this information we can find the decay rate "k" by solving for this parameter in the formula, and using the natural log function to bring the exponent down:

A(t)=A_0\,e^{-k\,t}\\\frac{A_0}{2} =A_0\,e^{-k\,*22}\\\frac{A_0}{A_0*2} =e^{-k\,*22}\\\frac{1}{2} =e^{-k\,*22}\\ln(\frac{1}{2})=-k\,*22\\ k=-\frac{ln(\frac{1}{2})}{22} \\k=0.0315

Now we use this value for the decay rate "k" to calculate how long it would take to decay to 90% of the original dose;

A(t)=A_0\,e^{-0.0315\,t}\\0.9*A_0} =A_0\,e^{-0.0315\,t}\\\frac{0.9*A_0}{A_0} =e^{-0.0315\,t}\\0.9 =e^{-0.0315\,t}\\ln(0.9)=-0.0315\,t\\ t=-\frac{ln(0.9)}{0.0315} \\t=3.3447\,hours

7 0
3 years ago
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