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Sever21 [200]
4 years ago
7

Plastic Knives are sold in packs of 18 for 45p. Plastic Forks are sold in packs of 15 for 41p. Jace wants to buy the same number

of forks as knives.
What is the least amount of money Jace will be able to spend?
Mathematics
1 answer:
Flauer [41]4 years ago
6 0

Answer:

430p

Step-by-step explanation:

For this, we'll find the least common multiple for 15 and 18.

=> The least common multiple for 15 and 18 is 90

<u><em>Plastic Knives:</em></u>

Jace will buy 90 knives.  

=> Packets = 90/18 = 5 Packets

Money for 5 Packets = 5 * 45

=> 225p

<u><em>Plastic Forks:</em></u>

Jace will buy 90 forks also.

=> Packets = 90/15 = 6 Packets

Money fro 6 packets = 6 * 41

=> 205p

<u><em>Least Amount of Money Jace will spend</em></u> = 225p+205p

=> 430p

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Answer:

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Step-by-step explanation: I hope it helps :)

1.

Surface\: area=\:2\pi rh+2\pi r^2\\h = 2ft\\diameter = 2ft\\Radius = d/2=2/2=1ft\\\\A=( 2\times 3.141\times1\times2)+(2\times 3.141 \times 1^2)\\A = (12.564)+(6.282)\\A = 18.846\\A = 18.85ft^2

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Area \:of\: square = A=a^2\\A = 3^2\\A=9\\Area\:of \:one \:rectangle\: = (l\times b)\\ A = (8\times 3)\\A = 24cm^2\\\\A = 2(Area\: of\: square)+2(Area\: of \:rectangle)\\A = 2(9)+4(24)\\A = 18+96\\A =114cm^2

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Area \: of\: base=?\\ r = 7\:in\\h = 12\:in\\A = \pi \times r^2\\A = 3.141 \times 7^2\\A = 153.909\\\\Height \: of \:the \:cylinder = 12\:inches\\Circumference = 2\pi \times r\\C= 2 \times 3.141 \times 7\\ C =43.98\\\\S.A= 2B+Ch\\S.A = 2(153.909)+43.98(12)\\S.A = 307.818+527.76\\S.A =835.578

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Perimeter = a+b+c\\P = 10+8+6\\P = 24\\S.A =2B+Ph\\S.A = 2(24)+24(8)\\S.A =48+192\\S.A = 240\:yd^2

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