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ddd [48]
3 years ago
9

Find the area of the shaded region of the figure below. Each small square is 1 cm x 1cm.

Mathematics
2 answers:
geniusboy [140]3 years ago
7 0

Answer: 23 cm²

Step-by-step explanation:

Since the squares are each 1 cm × 1 cm, you can technically count all the shaded squares, but it is good to do it mathematically.

We can separate this shape into 1 parts. The top part sticking up is a square and the bottom, a rectangle. We find the area for both parts and add them together.

Square:

3 cm × 3 cm = 9 cm²

Rectangle:

2 cm × 7 cm = 14 cm²

Total:

9 cm² + 14 cm² = 23 cm²

forsale [732]3 years ago
5 0

Answer: 23 cm squared

Step-by-step explanation:

Since the area of each square is 1 cm squared.

We can count up the number of squares which will be the total area.

There are 23 squares so the area of the region is 23 cm squared.

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dimaraw [331]

Answer:

D or A

Step-by-step explanation:

(D) One circle : four triangles  

  Example:

One triangle is 1/4 of a circle

(A) One circle : four triangles

    Example:

If there is two circles, the triangles will double like it shows [evidences]

6 0
3 years ago
In Mr. Jegou’s neighborhood 35% of the houses are blue. Write the percent that do not live in blue houses as a decimal and a fra
konstantin123 [22]

Answer:

65%

Step-by-step explanation:

65% + 35%=100%

8 0
3 years ago
What is the square root of 1,024
Shkiper50 [21]
1024 can be factored into 
<span>2(512) </span>
<span>=2^2(256) </span>
<span>=2^3(128) </span>
<span>=2^4(64) </span>
<span>=2^5(32) </span>
<span>=2^6(16) </span>
<span>=2^10 </span>

<span>Therefore, </span>
<span>√1024 = √(2^10) = 2^5 = 32</span>
4 0
3 years ago
5/7 = x/11 round your answer to the nearest tenth.
Scilla [17]

Answer:

7.9

Step-by-step explanation:

Multiply both sides of the equation by 11. This cancels out the fraction so 11 * 5/7 = x

lmk if I misunderstood the question or need to elaborate

6 0
3 years ago
Read 2 more answers
BRAINLIEST ASAP! PLEASE ANSWER!!!!!
hodyreva [135]
Similarities: They both are polynomials of degree 2, both of their graphs is a parabola, both have either 2 or 0 real solutions, they are both continuous functions over R 
(DOS= difference of two squares, PST=perfect square trinomial 
Differences: PST has three terms, whereas the difference of squares has 2. PST's factors are both the same, whereas DOS's elements are conjugates of each other. DOS can always be factored into two distinct polynomials with rational coefficients, whereas PST has two same polynomial factors.

7 0
3 years ago
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