Find the area of the shaded region of the figure below. Each small square is 1 cm x 1cm.
2 answers:
Answer: 23 cm²
Step-by-step explanation:
Since the squares are each 1 cm × 1 cm, you can technically count all the shaded squares, but it is good to do it mathematically.
We can separate this shape into 1 parts. The top part sticking up is a square and the bottom, a rectangle. We find the area for both parts and add them together.
Square:
3 cm × 3 cm = 9 cm²
Rectangle:
2 cm × 7 cm = 14 cm²
Total:
9 cm² + 14 cm² = 23 cm²
Answer: 23 cm squared
Step-by-step explanation:
Since the area of each square is 1 cm squared.
We can count up the number of squares which will be the total area.
There are 23 squares so the area of the region is 23 cm squared.
You might be interested in
Answer:
-13x+8
Step-by-step explanation:
add the x's including negatives
Answer:
D 192
Step-by-step explanation:
used: new: total
4: 1 : 5
We have 240 stamps
240/5 = 48
Multiply each number by 48
used: new: total
4*48: 1*48 : 5*48
192 : 48 : 240
There are 192 used stamps and 48 new stamps in his collections
Answer:
-10
Step-by-step explanation:
-2 + ? = -12
+2 +2
?= -10
Answer:
Step-by-step explanation:
since sin theta = 3/4, opposite length = 3 units and hypotenuse length = 4 units
by pythagoras' theorem, adjacent length =
thus cos theta = adjacent/hypotenuse =
Answer:
<u>shape</u> <u> </u> <u>of</u> <u> </u> <u>bases</u> <u> </u> <u>is</u> <u> </u> <u>rectangle</u> <u>.</u> <u>name</u> <u> </u> <u>of</u> <u> </u> <u>solid</u> <u> </u> <u>figure</u> <u> </u> <u>is</u> <u> </u> <u>cuboid</u> <u>.</u> <u>perimeter</u> <u> </u> <u>of</u> <u> </u> <u>base</u> <u> </u> <u>=</u> <u>2</u> <u>(</u> <u>1</u> <u>+</u> <u>2</u> <u>)</u> <u>=</u> <u>6</u> <u>m</u> <u>the</u> <u> </u> <u>height</u> <u> </u> <u>of</u> <u> </u> <u>prism</u> <u> </u> <u>=</u> <u>4</u> <u>m</u> lateral surface area =<u>perimeter</u> <u> </u> <u>of</u> <u> </u> base × <u>height</u> <u> </u> of the prism. the area of base=<u>l</u> <u>*</u> <u>b</u> <u>=</u> <u>2</u> <u>*</u> <u>1</u> <u>=</u> <u>2</u> <u> </u> <u>m²</u> <u>For</u> <u> </u> <u>any</u> <u> </u> <u>prism</u> <u> </u> <u>surface</u> <u> </u> area=<u>lateral</u> <u> </u> <u>area</u> <u> </u> <u>+</u> <u> </u> <u>2</u> <u> </u> <u>area</u> <u> </u> <u>of</u> <u> </u> <u>base</u> <u>the</u> <u> </u> <u>surface</u> <u> </u> <u>area</u> <u>=</u> <u>6</u> <u>*</u> <u>4</u> <u>+</u> <u>2</u> <u>*</u> <u>2</u> <u>=</u> <u>2</u> <u>8</u> <u>m</u> <u>²</u>