Answer:
$420
Step-by-step explanation:
(100 - 40)x = 60x
60x - 20 = 40x
0.4x = $168
x = $168/0.4 = $420
Answer:
Step-by-step explanation:
1) 2/9 = 185/x
2x = 1665
x = 832.5 or 8.325 meters
2) unit rate is the cost of one unit
i.e a dozen eggs cost $1.20 that
would be 10 cents each
3) 300 tissues for $3.75 vs. 250 for $2.99
one is 1.24 cents per tissue
the other 1.19 ... the 250 package is a better buy
Answer:
0.13% of students have scored less than 45 points
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
About what percent of students have scored less than 45 points?
This is the pvalue of Z when X = 45. So
has a pvalue of 0.0013
0.13% of students have scored less than 45 points
Answer:
4 units a minute
Step-by-step explanation:
34 to -34 is 68 units. Divided by 17 is 4, therefore 4 units in 1 minute.
What is the outlier in the following data set:<br>
15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya
Step-by-step explanation:
The steps to find an outlier:
1. Put the data in numerical order.
2. Find the median.
3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.
The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.
4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.
5. Multiply...1.5 * IQR
6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.
7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.
For your data....the median, Q2 is
(43+38)/2 = 40.5.
Q1 = (30+26)/2 = 28.
Q3 = (54+52)/2 = 53
The IQR is 53 - 28 = 25
1.5 * IQR = 37.5
Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.
Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.
My conclusion is that there are no outliers in this data.
I hope this helps!
