Answer:
Area = 297cm²
Step-by-step explanation:
Let Polygon be ABCDE
Draw a line CE parallel to AB which make right angles at F.
now, CE = AB
also, CF = FE = 22 / 2 = 11cm
and the line drawn from the vertex of the D = 19cm to G on AB.
AE = BC = FG = 8cm
so, FD = 19 - 8 = 11cm
Now the Area.
Area of the polygon = Area of the Rectangle ABCE + 2 x Area of either Triangle
(we need not calculate both the area of triangle as two sides of the triangle is equal)
Area of the Rectangle ABCE = l x b
here l = 22 cm and b = 8cm
= 22 x 8 = 176cm² ---------------(i)
2 x Area of either Triangle = 2 x 1/2 x b x h
here, b(CF or EF) = 11cm and h(FD) = 11cm
= 11 x 11 = 121cm² ----------------(ii)
Area of the polygon = Area of the Rectangle ABCE + 2 x Area of either Triangle
From (i) and (ii),
Area = 176 + 121
Area = 297cm²
A, expect the second term (2xy) should be just 2y
Answer:
U=-50
Step-by-step explanation:
X^2+y^2-6x+4y+18=0
x^2-6x+y^2+4y+18=0
x^2-6x+9+y^2+4y+4 =-18+9+4
(x-3)^2+(y+2)^2=-5
-5 is the minimum value of the given circle
The missing length .
Solution:
The image of the answer is attached below.
In figure ABCD, AB = 4, BC = 10
In figure PQRS, PQ = x, RS = 6
Given figures are similar.
If two figures are similar, then the sides are proportionate to each other.
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Do cross multiply.
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To reduce the length, divide both numerator and denominator by 2.
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Hence, the missing length .