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Afina-wow [57]
3 years ago
13

Find (3.3 × 10^4) + (1.9 × 10^5)

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0

Answer:

2.23 \times 10^{5}

Step-by-step explanation:

We have to find the sum of two numbers following the steps as described in the question.

The question is in the form of fill in the blanks.

Now, the given sum is (3.3 \times 10^{4} )+(1.9 \times 10^{5} )

= (3.3 \times 10^{4} )+(19 \times 10^{4} )

= (3.3+19) \times 10^{4}

= 22.3 \times 10^{4}

= 2.23 \times 10^{5} (Answer)

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Answer:

A) 33

Step-by-step explanation:

180 - 105= 75

75 + 72 + x = 180

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3 0
2 years ago
The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer se
tankabanditka [31]

Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

<u><em>T-value Calculation</em></u>

<u><em>Pooled Variance= Sp²</em></u>

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65

s2x`1 = s2p/n1 = 566.65/25 = 22.67

s2x`2 = s2p/n2 = 566.65/20 = 28.33

t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3

The t-value is -0.30107.

The total degrees of freedom is = n1+n2- 2= 25+20-2=43

The critical region for two tailed test at significance level ∝ =0.05 is

t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

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2 years ago
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Step-by-step explanation:

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where m=slope of line and c=y intercept

The slope of line is given as  m=\frac{(Y2-Y1)}{(X2-X1)}

Solving for Redline:

From the given graph, redline passes through (-1,0) and (0,1)

The slope of Redline is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Redline is  m=\frac{(1-0)}{(0-(-1))}

The slope of Redline is  m=(1)

And Y-intercept is 1

The equation of a Redline is given as y=1x+1

Solving for Blue-line:

From the given graph, Blue-line passes through (-1,0) and (0,2)

The slope of Blue-line is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Blue-line is  m=\frac{(2-0)}{(0-(-1))}

The slope of Blue-line is  m=(2)

And Y-intercept is 2

The equation of a Blue-line is given as y=2x+2

The Correct option is D). y=1x+1 And y=2x+2

7 0
3 years ago
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