Albert bought 2 pounds of catfish and 2 pounds of salmon
Let c represent the amount of catfish in pounds and s represent the amount of salmon in pounds.
He spent a total of $12 on salmon and catfish and bought a total of 4 pounds. Hence:
c + s = 4 (1)
4c + 2s = 12 (2)
Solving equations 1 and 2 simultaneously gives:
c = 2, s = 2
Albert bought 2 pounds of catfish and 2 pounds of salmon
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Answer:
9.34%
Step-by-step explanation:
p = 4%, or 0.04
n = Sample size = 667
u = Expected value = n * p = 667 * 0.04 = 26.68
SD = Standard deviation =
= 5.06
Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?
This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35
Since,
Z = (X - u) / SD
We have;
Z = (33.35 - 26.68) / 5.06
Z = 1.32
From the Z-table, the p-value of 1.32 is 0.9066
1 - 0.9066 = 0.0934, or 9.34%
Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.
Answer:
Distance formula is below
Step-by-step explanation:
Answer:
south since its the opposite