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2 years ago

Somebody help me please????????

1 answer:

7 0

8 $\frac{3}{8}$ - 5 $\frac{3}{4}$ = 8 $\frac{3}{8}$ - 5 $\frac{6}{8}$ = 7 $\frac{11}{8}$ - 5 $\frac{6}{8}$ = 2 $\frac{5}{8}$ liters = 2,625 litres - answer.

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A gallon of water weighs about 8.5 pounds. A container holds 412 gallons of water. How much does the water in the bucket wei

Alecsey [184]

We know that
1 <span>gallon of water weighs about -------------> 8.5 pounds.
so
412 gallons of water (container)-------> x
x=412*8.5-----> x=3502 pounds

the answer is
</span><span>the water in the bucket weigh 3502 pounds</span>

5 0

2 years ago

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One end of a ladder 32 feet long is placed 10 feet from the outer wall of a building that stands on the ground level. How far up

ladessa [460]

Answer:

30 ft

Step-by-step explanation:

This is a classic right triangle problem, where the length of the ladder represents the hypotenuse, where the ladder is lengthwise from the building is the base of the triangle, and what we are looking for is the height of the triangle. Pythagorean's Theorem will help us find this length.

$32^2-10^2=y^2$ so

1024 - 100 = y^2 and

y = 30.4 so 30 feet

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2 years ago

In quadrilateral abcd the measures of the angles are represented by measure angle a=6x-2, measure angle b=6x+5, measure angle c=

OleMash [197]

$\bf \textit{sum of all interior angles in a polygon}\\\\ S = 180(n-2)~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n = \stackrel{quadrilateral}{4} \end{cases} \\\\\\ \stackrel{\measuredangle a}{(6x-2)}~~+~~\stackrel{\measuredangle b}{(6x+5)}~~+~~\stackrel{\measuredangle c}{(8x+2)}~~+~~\stackrel{\measuredangle d}{(3x+10)}~~=~~180(4-2)$

$\bf 23x+15=180(2)\implies 23x+15=360\implies 23x=345 \\\\\\ x = \cfrac{345}{23}\implies \boxed{x = 15} \\\\\\ \stackrel{\measuredangle c}{8x+2}\implies 8(15)+2\implies 122$

8 0

2 years ago

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What is the answer to #14?

scZoUnD [109]

It think it’s 6x...!

7 0

3 years ago

Coordinate plane with quadrilaterals ABCD and EFGH with A at 0 comma 0, B at 2 comma 0, C at 3 comma negative 2, D at negative 1

charle [14.2K]

Answer:

No, quadrilaterals ABCD and EFGH are not similar because their corresponding segments are not proportional

Step-by-step explanation:

Corresponding sides have the same slope, so corresponding angles are congruent.

Side AB is 1/2 the length of side EF; side BC is equal to the length of FG, so corresponding sides are not proportional.

The two quadrilaterals are not similar because their corresponding segments are not proportional (last choice).

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2 years ago

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