Answer:
If I am not wrong I think the answer is the last one
Step-by-step explanation:
Answer: The speed of red horse = 44 feet per second and the speed of black horse = 35.2 feet per second.
Step-by-step explanation:
Given: A red horse and a black horse raced on a 1-mile-long circular racetrack.
Time taken by red horse = 120 seconds
Time taken by black horse = 150 seconds
Speed = ![\dfrac{Distance}{Time}](https://tex.z-dn.net/?f=%5Cdfrac%7BDistance%7D%7BTime%7D)
So, speed of red horse =![\dfrac{1}{120}\text{ mile per second}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B120%7D%5Ctext%7B%20mile%20per%20second%7D)
Since 1 mile = 5280 feet
Speed of red horse = ![\dfrac{5280}{120} =44\text{ feet per second}](https://tex.z-dn.net/?f=%5Cdfrac%7B5280%7D%7B120%7D%20%3D44%5Ctext%7B%20feet%20per%20second%7D)
Similarly,
Speed of black horse = ![\dfrac{5280}{150} =35.2\text{ feet per second}](https://tex.z-dn.net/?f=%5Cdfrac%7B5280%7D%7B150%7D%20%3D35.2%5Ctext%7B%20feet%20per%20second%7D)
Hence, the speed of red horse = 44 feet per second and the speed of black horse = 35.2 feet per second.
Answer:
0, -2
Step-by-step explanation:
The solution of an ordered pair is when the two lines intersect on one of the boxes.
In this case, the two lines meet at <u>0,-2</u>
<u />
The x is 0
The y is -2
Supplementary understanding of why it is negative:
Since the x (horizontal line) hasn't moved anywhere from the middle, the origin or (middle line) represents zero, therefore since it HAS NOT moved, it shall remain zero.
Since the y (vertical line) meets at "two-down", down would indicate it is negative (below the origin), and it only went down two boxes, so that's where the two came from.
:)
Answer: the solution to the inequality is -3 < x < 4. Graphically, this should be (2)
Step-by-step explanation:Note that x^2 - x - 12 factors to (x - 4)(x + 3) < 0, so we have:
(x - 4)(x + 3) < 0.The only way for (x - 4)(x + 3) to be negative is if x - 4 and x + 3 have opposite signs. This only occurs when:
(i) x - 4 < 0 AND x + 3 > 0
==> x < 4 AND x > -3; both occur when -3 < x < 4.
(ii) x - 4 > 0 and x + 3 < 0, which cannot happen at the same time.