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3 years ago

HELPPPPP !!!’

Mathematics

2 answers:

Karolina [17]3 years ago

8 0

Answer:

Step-by-step explanation:

That equals 85

-7

Take one away and add it onto the 2 so it can be 12. Then subtract 12 by 7 which is 5 then bring the 8 down. If you need a picture I can send it

never [62]3 years ago

4 0

Answer:

92-7=85

Step-by-step explanation:

My way of solving this is by first, lining the 92 above the 7 to have a clear visual, like this:

-7

Next, since 2-7=-5, it is best to cross out the 9, take away one, leaving 8, and giving that one to the two making it 12 like this:

8 12

-7

now, subtract 7 from twelve which is five, and place it underneath, and bring the 8 down because there is nothing in front of the 7 to subtract from the 8. Your problem will look like this:

8 12

-7

85:This is the answer.

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Two more than a number

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X+2 Hope this helps!

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2 years ago

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A) Both data sets multiplicative relationships. In Data Set 1, y is 3 times x and in data set 2 y is 3.5 times x B) Both data sh

Sladkaya [172]

For table # 1:

x= 1 * 3.5 = 3.5

x = 2*3.5 = 7

x = 3*3.5 = 10.5

x = 4* 3.5 = 14

For table #2

x=1 * 3 = 3

x =2 * 3 = 6

x = 3*3 = 9

x = 4* 3 = 12

Hence, the data sets show multiplicative relationships:

For data set 1 is 3.5 times x, and in data set 2 y is 3 times x.

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1 year ago

An adventurous dog strays from home, runs three blocks east, two blocks north, one block east, one block north, and two blocks w

Marrrta [24]

<h2>Answer:</h2>

<u>Distance = 360.55 m</u>

<u>Direction = North-East</u>

<h2>Step-by-step explanation:</h2>

In the question,

The adventurous dog starts from O, say.

He moves 3 blocks East = 300 m

then,

2 blocks North = 200 m

1 block East = 100 m

1 block North = 100 m

2 blocks West = 200 m

So,

Distance of the Dog's <u>final position</u> from the <u>initial position</u><u>.</u>

OE is given by,

In triangle OLE, using Pythagoras theorem,

$OE^{2}=OL^{2}+LE^{2}\\OE^{2}=(200)^{2}+(300)^{2}\\OE^{2}=40000+90000\\OE=360.55\,m$

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3 years ago

Evaluate for x = 3 and y = 4: x^-2y^2/x^0y^3 1/36 4/9 1024/9

GrogVix [38]

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Evaluating the numerator and denominator before evaluating

Using the rule of exponents

$a^{-n}$ ⇔ $\frac{1}{a^{n} }$ , $a^{0}$ = 1

Thus

$x^{-2}$ y² ← substitute values into expression

= $3^{-2}$ × 4² = $\frac{1}{9}$ × 16 = $\frac{16}{9}$

and denominator

$x^{0}$ $y^{3}$ = 1 × 4³ = 1 × 64 = 64

Now dividing

$\frac{16}{9}$ ÷ 64

= $\frac{16}{9}$ × $\frac{1}{64}$ ( cancel 16 and 64 )

= $\frac{1}{9(4)}$ = $\frac{1}{36}$

4 0

3 years ago

Triangle X Y Z is shown. Angle X Z Y is a right angle. Angle Z X Y is 60 degrees and angle X Y Z is 30 degrees. The length of hy

vladimir1956 [14]

Answer:

StartFraction StartRoot 3 EndRoot Over 3 EndFraction

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

we know that

In the right triangle XYZ

$cos(Y)=\frac{ZY}{XY}$ ---> adjacent side divided by the hypotenuse

substitute the values

$cos(30\°)=\frac{ZY}{4}$

Remember that

$cos(30\°)=\frac{\sqrt{3}}{2}$

substitute

$\frac{\sqrt{3}}{2}=\frac{ZY}{4}$

$ZY=(4)\frac{\sqrt{3}}{2}$

$ZY=2\sqrt{3}\ units$

step 2

$sin(Y)=\frac{XZ}{XY}$ --> opposite side divided by the hypotenuse

substitute the values

$sin(30\°)=\frac{XZ}{4}$

Remember that

$sin(30\°)=\frac{1}{2}$

$\frac{1}{2}=\frac{XZ}{4}$

$XZ=2\ units$

step 3

$tan(Y)=\frac{XZ}{ZY}$ --> opposite side divided by adjacent side

substitute the values

$tan(Y)=\frac{2}{2\sqrt{3}}$

$tan(Y)=\frac{1}{\sqrt{3}}$

Simplify

$tan(Y)=\frac{\sqrt{3}}{3}$

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3 years ago

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