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sasho [114]
3 years ago
6

Need help on 11, 12, and 13

Mathematics
1 answer:
Sati [7]3 years ago
7 0
11. is 25°
(Both triangles have two congruent angles which means the 3rd angle is bound to be the same. Just add the 90° and the 65° to get 155 and subtract from 180° because all triangles equal 180°)
12. is 25°
(Same as before, two of the angles are congruent so the third one is the same. Add all of the angles together and have them equal 180° because their is a variable present. 2x+60+70=180 or 2x+130=180. subtract 130 from both sides to get the equation 2x=50 and then divide both sides by 2 to get x=25.)
13. y=14 and x=11.6 (assuming m<d says 15x ÷ 2 because I couldn't really read it)
(m<a = m<d and m<b = m<e because they are lined up together in the ABC and DEF equation. so 3y=42 and (15x÷2=87)
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What is<br> -15 times the square root of 10 divided by 9? And whats the square root of that answer?
morpeh [17]
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Hope this helped :)
6 0
3 years ago
The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?
Jet001 [13]

Answer:

The roots are x = (\frac{3}{2}, -2), which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question, we have that:

2x^2 + x - 6 = 0

Which is a quadratic equation with a = 2, b = 1, c = -6. So

\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49

x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}

x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2

So the roots are x = (\frac{3}{2}, -2), which is given by option C.

3 0
3 years ago
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