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Flura [38]
2 years ago
14

What is the slope of the line that passes through (5,4) and (7, 10)?

Mathematics
1 answer:
GrogVix [38]2 years ago
5 0

slope = (y2-y1)/(x2-x1)

m=(10-4)/(7-5)

m =6/2

m=3

Choice A

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4 over 12 times 8 over 20

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=1/3 * 2/5

=2/15

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Multiple Choice Find<br> the value of x.<br> A 5 B 215<br> C 52 D 1<br> 10
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Answer:

5 x Square root:2

Step-by-step explanation:

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2 years ago
Tomas and Tasha were hiking at a speed of 3.5 mph. On their way back, they were tired and their speed was 2 mph. How long was th
Anna35 [415]

 To get the length of the route use the expression for speed,

Distance = Speed × Time

Length of the route is 7 miles.

It's given in the question,

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Therefore, distance travelled by both with the speed of 2 mph one way will be,

 Distance = 3.5t [Here, t = time ]

Speed of both while coming back = 2 mph

And the time taken = t + (1 hour 30 minutes)

                                 = (t + 1.5) hours

Therefore, distance travelled while coming back = Speed × Time

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Since, length of the route is same both ways,

3.5t = 2(t + 1.5)

3.5t = 2t + 3

3.5t - 2t = 3

1.5t = 3

t = 2 hours

Now substitute the value of t in the expression to get the distance of the route,

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Learn more,

brainly.com/question/1955818

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2 years ago
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True or false: a pair of straight angles can also be adjacent angles
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions. the statement "<span>a pair of straight angles can also be adjacent angles" is true 

</span>There are some special relationships between "pairs<span>" of </span>angles<span>. </span>Adjacent Angles<span> are two </span>angles<span> that share a common vertex, a common side, and no common interior points. (They share a vertex and side, but do not overlap.) A Linear </span>Pair<span> is two </span>adjacent angles<span>whose non-common sides form opposite rays.</span>
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2 years ago
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Answer fast its sue by end of class
shtirl [24]

Step-by-step explanation:

question 1. Solve the equation 8-7/10 c = 6 - 1/5c for c

8 - 7/10c = 6 - 1/5c

subtract 8 from both sides:

8 - 7/10c - 8 = 6 - 1/5c - 8

- 7/10c  = -2 - 1/5c

add 1/5c to both sides:

- 7/10c + 1/5c = -2 - 1/5c  + 1/5c

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change to common denominator:

- 7/10c+ 2/10c = -2

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multiply both sides by -2:

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c = 4

___________________________________

question 2. 75 - 3.5y - 4y = 4y + 6 for y

75 - 3.5y - 4y = 4y + 6

75 - 7.5y = 4y + 6

add 7.5y to both sides:

75 - 7.5y + 7.5y = 4y + 6 + 7.5y

75 = 11.5y + 6

subtract 6 from both sides:

75 - 6 = 11.5y + 6 - 6

69 = 11.5y

divide both sides by 11.5:

69/11.5 = 11.5y/11.5

y = 6

___________________________________

Question 3. Solve the equation 16.5 + 2.75h = 9h + 7.5 − 4.25h for h.

16.5 + 2.75h = 9h + 7.5 − 4.25h

16.5 + 2.75h = 4.75h + 7.5

subtract 7.5 from both sides:

16.5 + 2.75h - 7.5 = 4.75h + 7.5 - 7.5

9 + 2.75h =  4.75h

subtract 2.75h from both sides:

9 + 2.75h - 2.75h =  4.75h - 2.75h

9 = 2h

divide both sides by 2:

9/2 = 2h/2

h = 9/2

6 0
1 year ago
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