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3 years ago

Which values of

Mathematics

1 answer:

I am Lyosha [343]3 years ago

7 0

83x + P = 83x + Q subtract 83x from both sides

P = Q

The equation has no solution for P different Q (P ≠ Q).

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The Blair family was one of the first to come to the original 13 colonies (now part of the USA). They had 4 children. Assuming t

Mumz [18]

Answer:

31.25% probability that the Blair family had at least 3 girls

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it was a girl, or it was not. The probability of a child being a girl is independent of any other children. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

They had 4 children.

This means that $n = 4$

The probability of a child being a girl is 0.5

This means that $p = 0.5$

Probability of at least 3 children:

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{4,3}.(0.5)^{3}.(0.5)^{1} = 0.25$

$P(X = 4) = C_{4,4}.(0.5)^{4}.(0.5)^{0} = 0.0625$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 0.25 + 0.0625 = 0.3125$

31.25% probability that the Blair family had at least 3 girls

3 0

3 years ago

Meg received a 3% increase in pay, She was making $690/week

jekas [21]

Answer:

$20.70 increase per week!

Step-by-step explanation:

multiply 690 * 0.03 (aka 3%) to get 20.7 which equals $20.70

if you want to know how much she made the next week altogether, add 690 + 20.70 to get $710.70!

8 0

2 years ago

Read 2 more answers

Each Friday, the school prints 400 copies of the school newsletter. The equation c = 400w models the relationship between the nu

timofeeve [1]

Answer:

the answers are:

5 0

3 years ago

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Solve for e. T=e29 e=±3T√T e=±3T e=±3T√ e=±9T√

Anon25 [30]

Answer:

option (3) is correct.

$e= \pm 3\sqrt{T}$

Step-by-step explanation:

Given $T=\frac{e^2}{9}$

We have to solve for e.

Consider the given statement,

$T=\frac{e^2}{9}$

Cross multiply, we get,

$\Rightarrow 9T={e^2}$

Taking square root both sides , we get,

$\Rightarrow \sqrt{9T}=e$

We know square root of 9 is 3.

$\Rightarrow \pm 3\sqrt{T}=e$

Thus, option (3) is correct.

$e= \pm 3\sqrt{T}$

4 0

2 years ago

Ivan has 6 times as many blue beads as red beads. he has 49 red and blue beads in all. how many blue beads does Ivan have

salantis [7]

Let

x--------> the number of blue beads

y--------> the number of red beads

we know that

$x+y=49$

$x=49-y$ -------> equation $1$

$x=6y$ ------> equation $2$

equate equation $1$ and equation $2$

$49-y=6y\\ 6y+y=49\\ 7y=49\\\\ y=\frac{49}{7} \\ \\ y=7$

find the value of x

$x=6*7\\ x=42$

therefore

the answer is

Ivan has $42$ $blue beads$

3 0

3 years ago

Read 2 more answers