Dark energy and dark matter seem over analyzed, although they are no different than gravity and wind. Dark energy can be the pulling caused by black holes, stars, and large planets. Dark matter also is just the effect of cosmic dust and debris pushed from explosions but also pulling caused by distant gravitational bodies.
Answer:
The new volume is 63583 L
Explanation:
Step 1: Data given
The initial volume of the balloon = 5.37 * 10^4 L
The initial pressure = 0.995 atm
The initial temperature = 32.0 °C = 305.15 K
The pressure decreased to 0.720 atm
The temperature decreased to -11.7 °C = 261.45 K
Step 2: Calculate the new volume
P1*V1 / T1 = P2*V2/T2
⇒with P1 = the initial pressure = 0.995 atm
⇒with V1 = the initial volume = 5.37 *10^4 L
⇒with T1 = the initial temperature = 305.15 K
⇒with P2 = the decreased pressure = 0.720 atm
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the decreased temperature : 261.45 K
(0.995 * 5.37*10^4)/305.15 = (0.720 * V2) / 261.45
V2 = 63583 L
The new volume is 63583 L
Minerals need to be solid with a crystalline structure. Ice has these properties, liquid water does not. (i hope that helps you)
Answer:
You must remove 
.
Explanation:
There are three heat transfers in this process:
Total heat = cool the vapour + condense the vapour + cool the liquid
q = q₁ + q₂ + q₃
q = nC₁ΔT₁ + nΔHcond + nC₂ΔT₂
Let's calculate these heat transfers separately.
Data:
You don't give "the data below", so I will use my best estimates from the NIST Chemistry WebBook. You can later substitute your own values.
C₁ = specific heat capacity of vapour = 90 J·K⁻¹mol⁻¹
C₂ = specific heat capacity of liquid = 115 J·K⁻¹mol⁻¹
ΔHcond = -38.56 kJ·mol⁻¹
Tmax = 300 °C
b.p. = 78.4 °C
Tmin = 25.0 °C
n = 0.782 mol
Calculations:
ΔT₁ = 78.4 - 300 = -221.6 K
q₁ = 0.782 × 90 × (-221.6) = -15 600 J = -15.60 kJ
q₂ = 0.782 × (-38.56) = -30.15 kJ
ΔT = 25.0 - 78.4 = -53.4 K
q₃ = 0.782 × 115 × (-53.4) = -4802 J = 4.802 kJ
q = -15.60 - 53.4 - 4.802 = -50.6 kJ
You must remove of heat to convert the vapour to a gas.
Answer:
HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)
Explanation:
Aqueous solution of HCl and aqueous solution of KOH react as follow:
HCl(aq) + KOH(aq) —>
In solution, HCl and KOH will dissociates as follow:
HCl —> H+ + Cl-
KOH —> K+ + OH-
During the reaction, a double displacement reaction occur as shown below:
H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-
The elemental equation is given below:
HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)
