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Bond [772]
3 years ago
12

What would be the best product to neutralize battery acid

Chemistry
1 answer:
Anna [14]3 years ago
7 0

Answer:

Baking Soda a base

Explanation:

We know that to neutralize an acid we add base to it. Baking Soda is a type of base so when we add Baking Soda or any other base to battery acid or any other acid we can neutralize it and get salt and water.

Acids are the substance which are sour in taste and can turn blue litmus paper red. For example, Lemon and Orange.

Bases are the substance which are bitter in taste and can turn red litmus paper blue. For example, Baking Soda and Soap.

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Any two physical properties of salt​
Anna007 [38]

Explanation:

-Salt is a white cubic crystals. ...

-It is odorless but has strong salty taste.

-Solubility in water is different at different temperatures.

-Hygroscopic(ability of a substance to attract and hold water molecules from the surroundings).

-Melting point of salt is 800.8 degree Celsius

3 0
3 years ago
Which of the following elements have seven valance electrons in its outer shell?
lina2011 [118]

Answer:

Flourine

Explanation:

Its at the 17 group number which are where the halogens are located.

8 0
3 years ago
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How to combine chemical equations
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6 0
3 years ago
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Determine the mass of 2.75 moles of CaSO4. Record your work and your answer.
maw [93]

Explanation:

RFM \:  = 160 \: g \\ 1 \: mole \: weighs \: 160 \: g \\ 2.75 \: moles \: weighs \:  \frac{2.75 \times 160}{1} g \\  = 440 \: g

6 0
3 years ago
How much energy would be produced from the reaction of 2.40 moles hydrogen with 3.95 moles chlorine? ___ H2 + ___ Cl2 ___ HCl ΔH
True [87]

Answer:

How much energy would be produced from the reaction of 2.40 moles hydrogen with 3.95 moles chlorine?

H_2 +  Cl_2 -> 2HCl ,  deltaH = -554 kJ

Explanation:

Given,

2.40 moles hydrogen reacts with 3.95 moles chlorine.

From the balanced chemical equation,

1mol. of H2 reacts with 1mol. of Cl2

then,

2.40mol. of H2 reacts with ----?mol of Cl2

=>2.40 mol. H2 * \frac{1mol. Cl2}{1mol. H2} \\=2.40 mol. Cl2

So, the remaining moles of Cl2 is in excess.

The limiting reagent is--- H2.

1mol. of H2 releases --- 554kJ of energy

then,

2.40mol of H2 releases ---- ?

=>2.40mol * \frac{554kJ}{1 mol.} \\=1329.6kJ

Answer is: deltaH =-1329.6kJ

3 0
3 years ago
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