Question

Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the difference.
1. (–3x3 + 5x2 + 4x – 7) + (–6x3 + 2x – 3)
2. (–3x3) + 5x2 + 4x + (–7) + (–6x3) + 2x + (–3)
3. [(–3x3) + (–6x3)] + [4x + 2x] + [(–7) + (–3)] + [5x2]
4. –9x3 + 6x + (–10) + 5x2
5. –9x3 + 5x2 + 6x – 10

Answer 1

Answer: Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

Step 2: Removing parenthesis

Step 3: Grouping like terms

Step 4: Combing like terms

Step 5: Writing the final expression in standard form

Step-by-step explanation: First expression :$6x^3-2x + 3$

Second expression : $-3x^3+5x^2+4x-7$.

We need to subtract $6x^3-2x + 3$ from $-3x^3+5x^2+4x-7$.

Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

$(-3x^3+5x^2+4x-7)+(-6x3+2x-3)$

Step 2: Removing parenthesis

$(-3x^3) +5x^2+4x + (-7) + (-6x^3) + 2x + (-3)$

Step 3: Grouping like terms

$[-3x^3) + (-6x^3)] + [4x + 2x] + [(-7) + (-3)] + [5x^2]$

Step 4: Combing like terms

$-9x^3 + 6x + (-10) + 5x^2$

Step 5: Writing the final expression in standard form

$-9x^3 + 5x^2 + 6x-10$

Answer 2

Answer:

The answer on Edg is

1. wrote as addition of the additive inverse

2. wrote terms as addition of opposite

3. grouped like terms

4. combined like terms