The sample std. dev. will be (14 inches) / sqrt(49), or (14 inches) / 7, or 2 inches.
Find the z score for 93.8 inches:
93.8 inches - 91.0 inches 2.8 inches
z = ------------------------------------- = ----------------- = 1.4
2 inches 2 inches
Now find the area under the standard normal curve to the left of z = +1.4.
My calculator returns the following:
normalcdf(-100,1.4) = 0.919. This is the probability that the mean annual precipitation during those 49 years will be less than 93.8 inches.
The triangles are shown to be similar, therefore
The answer is 9 units
J can find the height of the fifth member on this way
S=150
S1=153
S2=150
S3=151
S4=152
S5=?
S= (s1+s2+s3+s4+s5)/5:
5*150= <span>153+150+151+152+S5
S5=5*150-606=750-606=144
Answer is 144 cm</span>
Answer:100
Step-by-step explanation:
Answer:
5 seconds
Step-by-step explanation:
In 5 seconds it will be at 98 meters
x = -b/2a
x = -20/2(-2) = -20/-4 = 5