The equation of the line would be
y = mx+b
where m is the slope, b is the y intercept.
<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept
and the base is y intercept divided by slope. Therefore,</span>
A = b^2/2m
At point (2,5)
5 = 2m+b
Substitute that in the area
A = b^2/5-b
to find the least area, differentiate the area with respect to the height and equate it to 0
dA/db = 0
<span>find b and
use that to find m. Then, you can have the equation of the line.</span>
Answer:
y = 100x + 400
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 400) and (x₂, y₂ ) = (1, 500) ← 2 points from the table
m =
= 100
note the line crosses the y- axis at (0, 400) ⇒ c = 400
y = 100x + 400 ← equation of line
Answer:
Only the first pair can be so mapped
Step-by-step explanation:
Reflection across AB and translation will leave the segment corresponding to AB having the same "north-south" (vertical) orientation. The reflection will reverse the clockwise ordering of corresponding vertices.
- selection 2: segment AY is not vertical
- selection 3: the ordering of the vertices is unchanged, not reversed
- selection 4: segment XY is not vertical
Answer:
i think it would be 12.4 sugar needed for a batch
Answer:
x=60,150,240,330
Step-by-step explanation:


Take the arc cot of both sides


Remember cotangent has a period of 180 degrees

where n is 0, 1,2,3,4,5.....
Isolate x.

where n is 0, 1,2,3,4,5,6.
Keep plugging in integers as long they are in the interval [0,360].
We get
60,150,240,330.