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3 years ago

Which numbers are rational and which are irrational?

Mathematics

1 answer:

Kamila [148]3 years ago

5 0

20π=irrational

√ 25=irrational

- 61.38=rational

52.1=rational

-√ 13=irrational

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A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult

klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = $\frac{Required outcomes}{Total possible outcomes}$

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>

<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = $\frac{n(Odd)}{Total}$ = $\frac{10}{20}$ = $\frac{1}{2}$ = 0.5

Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = $\frac{n(5)}{Total}$ = $\frac{4}{20}$ = $\frac{1}{5}$ = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = $\frac{2}{20}=\frac{1}{10}=0.1$

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0

3 years ago

In front of a store, there is a row of parking spaces. Cars park parallel to one another, with the front of each car facing the

Gelneren [198K]

The width used for the car spaces are taken as a multiples of the width of

the compact car spaces.

Correct response:

The store owners are incorrect

<h3 /><h3>Methods used to obtain the above response</h3>

Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.

We have;

Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)

New space design = 16·x + 9×(a·x) = x·(16 + 9·a)

When the dimensions of the initial and new arrangement are equal, we have;

10 + 12·a = 16 + 9·a

12·a - 9·a = 16 - 10 = 6

3·a = 6

a = 6 ÷ 3 = 2

a = 2

Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;

10 + 12·a < 16 + 9·a

Which gives;

x·(10 + 12·a) < x·(16 + 9·a)

Therefore;

The initial total car park space is less than the space required for 16

compact spaces and 9 full size spaces, therefore; the store owners are

incorrect.

Learn more about writing expressions here:

brainly.com/question/551090

5 0

2 years ago

The Pythagorean theorem is a2+b2=c2. Solve for b.

nata0808 [166]

Answer:

b = √c²-a²

Step-by-step explanation:

b² = c² - a²

b = √c²-a²

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2 years ago

Find the greatest four digit square number by division method

Agata [3.3K]

9999 is largest 4 digit number, and 100^2 is 10000, or 1 greater than the largest 4 digit number. This means that the closest square root of the largest perfect square is most likely 99. So 99^2 (9801)is the largest perfect square of four digits.

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3 years ago

How do u do question #15

Tom [10]

It is basically saying that you need to write 3 1/2 as ounces and pounds but in whole numbers. The answer is 3 pounds and 8 ounces.

7 0

2 years ago

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