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frez [133]
3 years ago
12

if a normal distribution has a mean of 132 and a standard devistion of 20, what is the value that has a z score of 1.8?

Mathematics
2 answers:
notsponge [240]3 years ago
5 0
The value would be 168.

The formula for a z-score is
z = (X-μ)/σ

Using our information, we have 
1.8 = (X-132)/20

Multiply both sides by 20:
1.8(20) = ((X-132)/20)*20
36 = X-132

Add 132 to both sides:
36+132 = X-132+132
168 = X
nikklg [1K]3 years ago
3 0

for people that have 3.6 instead of 1.8 you do the same thing,

3.6=(x-132)/20 it would be a.204 <---- apex.

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