Elimination method:
4m = n + 7
3m + 4n + 9 = 0
<em>First, let's get the equations in the same form.</em>
4m - n - 7 = 0
3m + 4n + 9 = 0
<em>Now let's make multiply the first equation by 4 so we can eliminate n.</em>
16m - 4n - 28 = 0
+3m + 4n + 9 = 0
<em>Now we can add the equations.</em>
16m + 3m - 4n + 4n - 28 + 9 = 0
19m + 0n - 19 = 0
19m - 19 = 0
19m = 19
<em>m = 1</em>
<em>Now we put m back into one (or both) of the original equations.</em>
4(1) = n + 7
4 = n + 7
<em>n = -3</em>
<em>If you plug m into the other equation, you get the same result.</em>
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Substitution method:
4m = n + 7
3m + 4n + 9 = 0
<em>With this method, we plug one of the equations into the other one. I'm going to use m in the second equation as a substitute for m in the second equation.</em>
3m + 4n + 9 = 0
3m = -4n - 9
m = (-4/3)n - 3
<em>Now I can substitute the right side into the first equation like so:</em>
4[(-4/3)n - 3] = n + 7
(-16n)/3 - 12 = n + 7
(-16n)/3 = n + 19
-16n = 3(n + 19)
-16n = 3n + 57
0 = 16n + 3n + 57
0 = 19n + 57
0 = 19n/19 + 57/19
0 = n + 3
<em>-3 = n</em>
<em>And then we put that back into one of the original equations.</em>
4m = n + 7
4m = -3 + 7
4m = 4
<em>m = 1</em>
Hopefully you learned something from this.
Answer:
It's equal to itself. Here are the two ways to do this problem. ↓
B is the value of q because you add the 4.4 and the 4.4 which u get 8.8
Answer:
m = 200N
Step-by-step explanation:
3000N = m(15m/s²) Divide both sides by 15 to find the mass
200N = m
Answer:
The maximum number of chocolate rabbits that can be made from 16 chocolate bars = 27
Step-by-step explanation:
3 chocolate bars can make at most 5 chocolate rabbits.
Therefore, maximum number of chocolate rabbits that can be made from 3 chocolate bars = 5
Now, we are given 16 chocolate bars and need to find maximum number chocolate rabbits that can be made from the given number of chocolate bars.
Hence, The maximum number of chocolate rabbits that can be made from 16 chocolate bars = 27
